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3 years ago

I am thinking of a number.

Mathematics

2 answers:

mash [69]3 years ago

8 0

Answer:

$21$

Step-by-step explanation:

Let $x$ be that number.

$12x-216=2x-6$

$12x-2x=-6+216$

$10x=210$

$10x/10=210/10$

$x=21$

21 is the number.

asambeis [7]3 years ago

8 0

Let n, equal that number.

12n - 216 = 2n - 6

Solve for n:

12n - 216 = 2n - 6

12n - 216 + 216 = 2n - 6 + 216

12n = 2n + 210

12n - 2n = 2n - 2n + 210

10n = 210

10n/10 = 210/10

n = 21

Therefore, the answer si 21.

Best of Luck!

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Find the discriminant 9x^2+14x+13=8x^2

tiny-mole [99]

Answer:

The discrimant of this equation is 144.

Step-by-step explanation:

First you have to move all the variables to one side to make the equation/expression into 0 by substracting 8x² to both sides :

9x² + 14x + 13 = 8x²

9x² + 14x + 13 - 8x² = 8x² - 8x²

x² + 14x + 13 = 0

It is given that the formula of discriminant is, D = b² - 4ac where a&b&c represent the number of the equation, ax²+bx+c = 0 :

x² + 14x + 13 = 0

D = b² - 4ac

= 14² - 4(1)(13)

= 196 - 52

= 144

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Read 2 more answers

Ayuda por favor

sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos similares, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo pequeño) y AP'' (triángulo grande), así como de los lados AM y AB, así como los lados AN y AC, así como los mismos ángulos en la misma distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2 (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

$\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }$

$\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}$

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

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2 years ago