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Inessa [10]
3 years ago
6

I am thinking of a number.

Mathematics
2 answers:
mash [69]3 years ago
8 0

Answer:

21

Step-by-step explanation:

Let x be that number.

12x-216=2x-6

12x-2x=-6+216

10x=210

10x/10=210/10

x=21

21 is the number.

asambeis [7]3 years ago
8 0

Let n, equal that number.

12n - 216 = 2n - 6

Solve for n:

12n - 216 = 2n - 6

12n - 216 + 216 = 2n - 6 + 216

12n = 2n + 210

12n - 2n = 2n - 2n + 210

10n = 210

10n/10 = 210/10

n = 21

Therefore, the answer si 21.

Best of Luck!

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Step-by-step explanation

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2 years ago
Julio bought tables and chairs for his restaurant. He bought 16 total items and spent $1800. Each table cost $150 and each chair
uysha [10]

Answer:

He bought 6 chairs and 10 tables.

Step-by-step explanation:

x+y = 16

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we got two equations :

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4 0
2 years ago
Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
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Answer:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

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Now we have all the values needed and if we replace into equation (b) we got:

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So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0
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Answer:

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