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Vesnalui [34]
3 years ago
7

Select the two figures that are similar to the 5 by 10 figure that is shown.

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

Figure (i) and (iv)

Step-by-step explanation:

Given:

Optional figure is given in attached file.

We need to find two figures that are similar to the 5 by 10 figure.

All the given figure are m\times n form.

Where m represent the number of rows and n represent the number of columns.

Solution:

Observe that in the given figure 5 by 10, the number of rows is 5 and number of columns is 10, that is, the number of columns is double of that the number of rows.

So we need to find two such figures whose number of columns is double of the number of rows.

From the given figures, figure (i) the number of rows is 2 and number of columns is 4, which is double of number of rows. so it is similar to 5 by 10 figure.

Similarly in figure (iv), the number of rows is 4 and number of columns is 8. so the number of columns is double the number of rows, so it is similar to the figure 5 by 10.

Therefore, the two figures that are similar to 5 by 10 figure are given in attached file such as (i) and (iv).

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(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

#SPJ4

5 0
1 year ago
Fill in the blanks<br>864+2006=--------+864<br><br>5351 +(574+799)= 574+(5351+_____)​
Mama L [17]

Answer:

2006

799

Step-by-step explanation:

Given the expression:

The right hand side of the sun must be equal to the left hand side ;

Therefore ;

864+2006=--------+864

The sum of 864 and 2006 must be equal to the right hand side sum ; hence

864+2006= 2006 +864

Similarly, the left hand side and right havd side must also be equal here ;

5351 + 574 + 799 = 574 + 5351 + 799

Hence, the missing value is 799

6 0
3 years ago
HELP :6 lb 5oz - 4lb 12oz ( there are 16 ounces in one pound) A.2lb 7oz B.1lb 7oz C1lb 9oz.
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Answer:

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Step-by-step explanation:


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aliya0001 [1]

Answer:

$6 per hour

Step-by-step explanation:

27/4.5=6

8 0
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A circle with circumference12 has an arc with a 330∘ degree central angle. What is the length of the arc?
posledela
The formula for arc length which is measured in units not degrees is \frac{ \beta }{360} *2 \pi r, where 2 pi r is the circumference.  We were given the circumference as 12 pi, so we can fill in the rest of the formula and the find the length of the arc that is intercepted by that 330° angle.  \frac{330}{360} *12 \pi gives us, after multiplying in the pi, an arc length of 34.56 units.
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3 years ago
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