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EleoNora [17]
3 years ago
7

Round 1,989,983,939 to the millions

Mathematics
2 answers:
IRISSAK [1]3 years ago
5 0
1,990.000,000 is the appropriate answer<span />
AysviL [449]3 years ago
4 0
1,020,000,000 and I'm going to moo to meet the character minimum moooooooooooooooooooooooooooooooooooooooooooooooooooooo
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In dealing with surface area, what is a net?
Tju [1.3M]

Answer:

the answer is a.

when dealing with surface area, a net is a two-dimensional figure that can be cut out and folded up to make a three-dimensional solid

5 0
3 years ago
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Reva is playing a bean-bag toss game. For each bag that misses the board, the player scores -8 points. Reva misses the board 4 t
erica [24]

Answer:

The answer is -32.

Step-by-step explanation:

Since there is no detailed information given about the game or the total tosses in the question, i will assume that the game is concluded when each player has had 4 tosses.

Considering the information that Reva missed the board 4 times out of her total 4 tosses in the game and each miss results in -8 points, her total score for those 4 tosses should be -8x4 = -32.

I hope this answer helps.

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3 years ago
A ball is kicked straight up into the air from a height of 48ft with an initial velocity of 88 ft/s. After how many seconds does
AlladinOne [14]

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67

Step-by-step explanation:

5 0
3 years ago
2x^2-12x-32=0 solution
Charra [1.4K]

Answer: x=−2 or x=8

Step-by-step explanation:

Step 1: Factor left side of equation.

2(x+2)(x−8)=0

Step 2: Set factors equal to 0.

x+2=0 or x−8=0

x=−2 or x=8

8 0
3 years ago
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You roll 4 fair, distinguishable, six-sided dice. What is the probability of rolling :______
Vikentia [17]

Answer:

a)0.25

b)0.375

Step-by-step explanation:

Possible outcomes when dice are rolled : 1 ,2 ,3,4,5 ,6

Even= 2,4,6  

Odd = 1 ,3 , 5

Probability of getting even =\frac{3}{6}=\frac{1}{2}

Probability of getting odd = \frac{3}{6}=\frac{1}{2}

4 dices are rolled together

a)P(3 even and 1 odd numbers)

P(3 even and 1 odd numbers)=^4C_3 (\frac{1}{2})^3 (\frac{1}{2})^1

P(3 even and 1 odd numbers)=\frac{4!}{3!1!} (\frac{1}{2})^3 (\frac{1}{2})^1 =0.25

b)P(2 even and 2 odd numbers)

P(2 even and 2 odd numbers)=^4C_2 (\frac{1}{2})^2 (\frac{1}{2})^2

P(3 even and 1 odd numbers)=\frac{4!}{2!2!} (\frac{1}{2})^2 (\frac{1}{2})^2=0.375

6 0
2 years ago
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