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ra1l [238]
3 years ago
6

Metal elements generally demonstrate low electronegativity and low ionization energy.

Chemistry
2 answers:
denpristay [2]3 years ago
6 0
False the answer is check
Pavel [41]3 years ago
3 0
The answer is False just took that test lol
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The number of Al atoms in 0.25 mol of Al2(SO4)3​
Harrizon [31]

Answer:

3.011 × 10²³ atoms of Al

Explanation:

Given data:

Number of moles of Al₂(SO₄)₃ = 0.25 mol

Number of atoms of Al = ?

Solution:

In one mole of Al₂(SO₄)₃  there are 2 moles of Al.

In 0.25 mol × 2 = 0.5 mol

1 mole of any substance contain 6.022 × 10²³ atoms.

In 0.5 moles of Al:

1 mole contain 6.022 × 10²³ atoms.

0.5 mol × 6.022 × 10²³ atoms/ 1 mol

3.011 × 10²³ atoms

4 0
3 years ago
1H2 + 2O2 -> 3Н2O. ​
makvit [3.9K]

Answer:

1H2 + O2 -> 2Н2O.

combination reaction.

7 0
3 years ago
What would be the result if the atmosphere was unable to move and exchange gases with Earth's other spheres?
Crazy boy [7]

There are four Earth's spheres: the geosphere, hydrosphere, biosphere and atmosphere.

The spheres interact with one other. For example, plants (biosphere) produce oxygen (atmosphere) from carbon dioxide (atmosphere).

Substances in different spheres are recycled and turned into other phases and forms. This is important cycle and without that, there is no life on Earth.

6 0
4 years ago
At STP, which gas sample has a volume of 11.2 liters?
Natasha2012 [34]

Answer:

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

Explanation:

Step 1: Data given

Volume of a gas at STP = 11.2 L

STP: Pressure = 1 atm  and temperature = 273 K

Step 2: Calculate volume

p*V= n*R*T

V = (n*R*T)/p

⇒with V = the volume of the gas = TO BE DETERMINED

⇒with n = the number of moles of the gas

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273 K

⇒with p = the pressure of the gas = 1 atm

A ) 0.250 mole of NH3

V = (0.250 * 0.08206 * 273) / 1

V = 5.6 L

B ) 0.500 mole of CO2

V = (0.500 * 0.08206 * 273) / 1

V = 11.2 L

C ) 0.750 mole of NH3

V = (0.750 * 0.08206 * 273) / 1

V = 16.8 L

D) 1.00 mole of CO2

V = (1.00 * 0.08206* 273) / 1

V = 22.4 L

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

3 0
4 years ago
Write the beta decay equation for the following isotope: 15/6 C?
vesna_86 [32]

Answer:

\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{7}^{15}\text{N}

Explanation:

The unbalanced nuclear equation is

\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \, ?

Let's write the question mark as a nuclear symbol.

\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

15 =  0 + A, so A = 15 -   0 = 15, and

 6 = -1 + Z, so Z  =   6 + 1 =    7

Then, your nuclear equation becomes

\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{7}^{15}\text{X}

Element 7 is nitrogen, so the balanced nuclear equation is

\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{7}^{15}\text{N}

8 0
4 years ago
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