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nikklg [1K]
3 years ago
8

The number of Al atoms in 0.25 mol of Al2(SO4)3​

Chemistry
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

3.011 × 10²³ atoms of Al

Explanation:

Given data:

Number of moles of Al₂(SO₄)₃ = 0.25 mol

Number of atoms of Al = ?

Solution:

In one mole of Al₂(SO₄)₃  there are 2 moles of Al.

In 0.25 mol × 2 = 0.5 mol

1 mole of any substance contain 6.022 × 10²³ atoms.

In 0.5 moles of Al:

1 mole contain 6.022 × 10²³ atoms.

0.5 mol × 6.022 × 10²³ atoms/ 1 mol

3.011 × 10²³ atoms

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The mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

<h3>How to calculate mass of an element in a compound?</h3>

According to this question, a 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O.

This means that the mass of sulfur in the 10.4g of CaSO4 is 10.4g - (3.06g + 4.89g) = 10.4g - 7.95g = 2.45g

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Therefore, the mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

Learn more about mass at: brainly.com/question/13672279

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