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nikklg [1K]
3 years ago
8

The number of Al atoms in 0.25 mol of Al2(SO4)3​

Chemistry
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

3.011 × 10²³ atoms of Al

Explanation:

Given data:

Number of moles of Al₂(SO₄)₃ = 0.25 mol

Number of atoms of Al = ?

Solution:

In one mole of Al₂(SO₄)₃  there are 2 moles of Al.

In 0.25 mol × 2 = 0.5 mol

1 mole of any substance contain 6.022 × 10²³ atoms.

In 0.5 moles of Al:

1 mole contain 6.022 × 10²³ atoms.

0.5 mol × 6.022 × 10²³ atoms/ 1 mol

3.011 × 10²³ atoms

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When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°
dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.30^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =  

m= molality = \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579

8.30^0C=1\times K_f\times 0.579

K_f=14.3^0C/m

Let Mass of solute (KBr) = x g

8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}

x=58.2g

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0
2 years ago
Choose the molecule or compound that exhibits dipole-dipole forces as its strongest intermolecular force.
LuckyWell [14K]

Answer:

SO2

Explanation:

Dipole-Dipole exist between parmanent dipoles in a molecule. THis means that molecule must have a parmanent dipole moment in it.

Example - HCl

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Among the molecules given in the list only SO2 and H2O exihibits parmanent moment. As BCl3 , CBr4 and H2 are symmetric compounds.

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3 years ago
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vlada-n [284]
The answer to that question is B
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3 years ago
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