In every molecule of
there is 8 atoms of Carbon.
IF we have 3.7 moles of
to find the number of moles of Carbon, just multiply by 8
3.7 * 8 = 29.6 mol Carbon
Hi
I think it’s B
Hopefully this helps!!
Answer & Explenation:
2H2 + O2 -> 2H20 is the balanced equation for the reaction of Hydrogen with Oxygen to form water so
If you have 32g of O2 this is a simple Dimensional analysis problem
32g O2 x 36.03056g H20/31.9988g O2 this way the O2 cancels out and you are left with just the H2O so your raw answer would be 36.0319112, then if your instructor requires a significant figure answer that would be to 2 significant figures the information you were given 32g O2, so as above 36g or Water are produced. Just a different way to view and solve the problem with the balanced equation so you can see the way everything relates to everything else. the molar masses of O2 and H2O are simply found my adding up 2 Oxygens 15.9994g x2 = 31.9988g and H2O = 2(1.00794) + 15.9994 = 18.01258 but you then have to multiply that by 2 because the reaction states you get 2 mols in the reaction so that is where I came up with the 36.03056g for the solution. Hope this helps. Dimensional Analysis is and can be one of the best ways to solve these problems, because not always are you going to be dealing with 1:2 ratios.
<h3><u>Answer;</u></h3>
= 5.1 g/L
<h3><u>
Explanation;</u></h3>
Using the equation;
PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.
Number of moles is 1 since one mole has a mass equivalent to the molar mass.
Therefore; We can find the volume and thus get the density.
<em>V = nRT/P</em>
<em> = (1 × 0.08206 × 237)/3.510</em>
<em> = 5.5408 L</em>
<em>Hence; Density = mass/volume </em>
<em> = 28.26 g/5.5408 L</em>
<em> = 5.1 g/L</em>
<em>The Density is 5.1 g/L or 0.005 g/cm³</em>
Answer:
128.98 g/Mol
Explanation:
ΔTb = Kb * m * i
Where;
ΔTb = boiling point elevation
Kb = boiling point constant
m = molality of the solution
i = Van't Hoff factor
Hence;
Where molality = number of moles of solute/mass of solvent in Kg
Number of moles of solute = mass/Molar mass
So;
80.61 - 80.10 = 2.53 * 13g/M/0.5 * 1
Where M is the molar mass of the solute
0.51 = 2.53 * 13g/M/0.5
0.51 = 2.53 * 13/M * 1/0.5
0.51 = 32.89/M * 1/0.5
0.51 * 0.5 = 32.89/M
0.255 M = 32.89
M = 32.89/0.255
M= 128.98 g/Mol
