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GuDViN [60]
3 years ago
8

Calcum chloride contains only calcum and chloride What is the fomula for this compound? fou need the Peodie Table for thia quest

ion to detemine he proups of these elemente and thus determine ther onzaon deo for the Podic Table of he Elements in he Introduction to the queton) You might ao choope to acpes he Express your answer as a chemical formule View Available His) C. AE4 CaCI
Chemistry
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

CaCl_2

Explanation:

Calcium is the element of the group 2 and period 4 which means that the valence electronic configuration is [Ar]4s^2.

Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is [Ne]3s^23p^5.

Thus, calcium losses 2 electrons to 2 atoms of chlorine and these 2 atoms of chlorine accepts each electron to form ionic bond. This is done in order that the octet of the atoms are complete and they become stable.

Ca         Cl

2            1

Cross multiplying the valency, We get, CaCl_2

Thus, the formula of calcium chloride is CaCl_2.

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Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.
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Answer: Solution A : [H_3O^+]=0.300\times 10^{-7}M

Solution B : [OH^-]=0.107\times 10^{-5}M

Solution C : [OH^-]=0.177\times 10^{-10}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

pH=-\log[H_3O^+]

pOH=-log[OH^-}

pH+pOH=14

[H_3O^+][OH^-]=10^{-14}

a. Solution A: [OH^-]=3.33\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M

b. Solution B : [H_3O^+]=9.33\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M

c. Solution C : [H_3O^+]=5.65\times 10^{-4}M

[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M

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