Answer:
∆H= <u>438 KJ/mol</u>
Explanation:
First, we have to find the <u>energy bond values</u> for each compound:
-) Cl-Cl = 243 KJ/mol
-) F-F = 159 KJ/mol
-) F-Cl = 193 KJ/mol
If we check the reaction we can calculate the <u>number of bonds</u>:

In total we will have:
-) Cl-Cl = 1
-) F-F = 3
-) F-Cl = 6
With this in mind. we can calculate the <u>total energy for each bond</u>:
-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol
-) F-F = (3*159 KJ/mol) = 477 KJ/mol
-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol
Now, we can calculate the total energy of the <u>products</u> and the <u>reagents</u>:
Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol
Products = 1158 KJ/mol
Finally, to calculate the total enthalpy change we have to do a <u>subtraction</u> between products and reagents:
∆H= 1158 KJ/mol-720 KJ/mol = <u>438 KJ/mol</u>
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I hope it helps!
Hi sorry
I don’t know
but maybe next time
I think that the government needs to get it together
Isotopes are variants of a particular chemical element which differ in neutron number, and consequently in nucleon number. All isotopes of a given element have the same number of protons but different numbers of neutrons in each atom.
The term isotope is formed from the Greek roots isos ("equal") and topos ("place"), meaning "the same place".