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nlexa [21]
2 years ago
12

when you put a book on a table the table pushes on the book is that newton's 1st,2nd,or 3rd law of motion ? 

Chemistry
1 answer:
ohaa [14]2 years ago
8 0
The table pushes the book and the book pushes the table
It's 3rd law
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Each covalent H bond is nonpolar.
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Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

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5 0
2 years ago
What is the balanced equation for the combustion of magnesium?
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Answer:

2Mg  +  O2 →  2MgO

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In all conbustion you should know, that reactans are an specific compound and O2, so the products must be CO2 and H2O, or in this case, the corresponding oxide.

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It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:

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The metal atom having molar mass as 87.62/mol is Strontium.

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