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iren [92.7K]
4 years ago
6

What is 6 1/2-(1 7/8)=?

Mathematics
2 answers:
kozerog [31]4 years ago
7 0

\frac{37}{8}
or 4.625
Yanka [14]4 years ago
6 0

the answer is 4.625.

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MZGFN= 4x + 10, mZNFE = 14x + 3,<br> and mzGFE=157º. Find m2NFE.
mojhsa [17]

Answer:

115°

Step-by-step explanation:

1. Calculate the value of x

\begin{array}{rcc}m\angle GFM + m\angle NFE & = & m\angle GFE\\4x + 10 + 14x + 3 & = & 157\\18x + 13 & = & 157\\18x & = & 144\\x & = & \dfrac{144}{18}\\ & = & 8\\\end{array}

2. Calculate m∠NFE

m∠NFE = 14x + 3 = 14(8) + 3 = 112 + 3 = 115

5 0
3 years ago
The length of a cart is 3.6 yards. What is the length in foot
Paul [167]

Answer:

10.8 feet.

Step-by-step explanation:

first you know that there are 3 ft per yard

then all you do is 3.6 times 3 which is 10.8 feet or 10 4/5 feet

5 0
3 years ago
3(-5x+3)=8x+9 how do i find x?
iVinArrow [24]

Answer:

No solution

Step-by-step explanation:

-15x+9=8x+9

-23x=0

No solution

6 0
3 years ago
Read 2 more answers
3.In 1995, the Educational Testing Service in Princeton, New Jersey (which administers SAT exam) re-centered the scores so that
Travka [436]

Answer:

38.22% probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they score between 900 and 1,100, or they score outside this range. The probability of a student scoring between 900 and 1,100 is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

About 40 percent of these students’ scores were between 900 and 1,100.

This means that p = 0.4.

a)Based on this estimate, what is the probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100?

This is P(X < 4) when n = 10. So

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0060

P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403

P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0060 + 0.0403 + 0.1209 + 0.2150 = 0.3822

38.22% probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100

8 0
4 years ago
What number is 15% of 63
Degger [83]
Take the number (63) and then divide it with 100, this gives you 1%. Then you want to multiply with with 15 in order to get 15%. The answer becomes:

\frac{63}{100}\cdot 15=9.45
6 0
4 years ago
Read 2 more answers
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