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3 years ago

Which of these standard form equations is equivalent to (x + 1)(x − 2)(x + 4)(3x + 7)?

Mathematics

1 answer:

Virty [35]3 years ago

8 0

Answer:

C. 3x^4 + 16x^3 + 3x^2 - 66x - 56

Step-by-step explanation:

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To find the difference of 7 - 3 5/12 how do you rename the 7

lawyer [7]

You would want to make it so it has 12 on the bottom. So you would multiply by 12. Which is 84. The you put it over 12. So it would be 84/12.

7 0

4 years ago

If using the method of completing the square to solve the quadratic equation

marysya [2.9K]

Answer:

Step-by-step explanation:

i need help too

6 0

4 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

8 0

3 years ago

Please answer correctly !!!! Will mark brainliest !!

jek_recluse [69]

Answer:

h(u)=-7/6u

Step-by-step explanation:

To write a formula for v in terms of u, you need to first isolate v.

4u+8v=-3u+2v

Add 3u to both sides:

7u+8v=2v

Subtract 8v from both sides:

7u=-6v

Divide both sides by -6:

v=-7/6u

Hope this helps!

5 0

3 years ago

Read 2 more answers

The front and back covers of a text book are each 0.3 thick between the cover are 200 sheets of paper each 0.008 cm thick how hi

shepuryov [24]

Answer: 1,000

Step-by-step explanation:

The height of 10 stacks of books would be a 1,000 because if it's 0.3 thick between covers of 200 sheets then 10 books would be a 1,000.

5 0

3 years ago