How many atoms of each element are present in the nucleotide adenine:C9H14N3O8P

Help me I promise if you answer all of this first and correctly and I get a good grade i will answer all of your question and I'

Tomtit [17]

Answer:

9. true

10. a.

5. a.

7. a

8. d.

14. c.

15. d.

11. false

12. true

13. a.

$hopethishelps$

8 0

3 years ago

How would each of the following procedural errors affect the results to be expected in this experiment? Give your reasoning in e

Digiron [165]

Answer:

a) if the liquid is not vaporized completely, then the condensed vapor in the flask contains the air which is initially occupied before the liquid is heated. When calculating the molar mass of the vapor the moles of air which are initially present are not excluded, so that the molar mass of the vapor would be an increase in value.

b) While weighing the condensed vapor, the flask should be dried. If the weighing flask is not dried then the water which is layered on the surface of the flask is also added to the mass of the vapor. Therefore, the mass of the vapor that is calculated would be increase.

c) When condensing the vapor, the stopper should not be removed from the flask, because the vapor will escape from the flask and a small amount of vapor will condense in the flask. Therefore, the mass of the condensed vapor would be In small value.

d) If all the liquid is vaporized, when the flask is removed before the vapor had reached the temperature of boiling water, then the boiling

temperature of that liquid would be lower than that of the boiling temperature of the water.Therefore, the liquid may have more volatility.

7 0

3 years ago

I really need help with it’s I don’t get it

8090 [49]

Explanation:

1. Chart shows the annual state spending in percentages, like on things to benefit both them and the public.

2. Estimate that the total is 50,000 spent. Multiply that by 0.07 for the 7% spent on highways. You get 3,500 total.

3. Add the total from the previous problem with the budget of 50,000 multiplied by 0.14 to find 14% of the entire budget. You have 3,500 for 7%, and 7000 for 14%. Add them together to get a total of 10,500.

4. A. They spend the most on other, a whopping 45%.

B. The chart shows the total percentages of the amount spent.

5. No. The graph has nothing to do with age.

3 0

3 years ago

Explain how we know that charge is conserved in this<br> reaction: Li+ CI → Lici

butalik [34]

Answer:

Charge is conserved due to the groups in which Lithium and Chlorine are located in the periodic table of the elements.

Explanation:

In the reaction $Li + Cl - > LiCl$ , we can examine the groups in which Li and Cl are found in the periodic table of the elements. Lithium appears in Group 1A, or the alkali metals group, indicating that it carries a charge of +1. Chlorine appears in Group 7A, or the halogen group, indicating that it carries a charge of -1. Because LiCl's constituent elements carry the same charges as previously mentioned, LiCl will have an overall charge of 0.

The chemical equation can then be rewritten as $Li^{+} + Cl^{-} - > LiCl$ , which, if looking at the individual charges of Li and Cl in lithium chloride, becomes $Li^{+} + Cl^{-} - > Li^{+}Cl^{-}$ . Adding the charges on the reactant and product sides of this chemical equation gives us zero in both locations, meaning that we have a charge of 0 on the reactant side and a charge of 0 on the product side. This indicates that charge is conserved in this reaction.

Another way to look at this is expressed in the valence electrons of Li and Cl. Li has an electron configuration of $1s^{2}2s^{1}$ , where the n = 2 electron shell has one of eight total electrons needed to fill the valence shell. This means that Li will easily lose one electron in order to have an electron configuration where the n = 1 electron shell is full, $1s^{2}$ , and become the $Li^{+}$ ion. Similarly, Cl has an electron configuration of $1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}$ (or $[Ne]3s^{2}3p^{5}$ ), meaning that the n = 3 electron shell is one electron away from becoming complete. Cl will easily gain one electron to have the electron configuration $[Ne]3s^{2}3p^{6}$ (or $[Ar]$ ) in order to have an electron configuration where the n = 3 electron shell is full, $3s^{2}3p^{6}$ , and become the $Cl^{-}$ ion. Thus, when Li and Cl bond, Li will lose the electron $[1, 0, 0, +\frac{1}{2}]$ and transfer it to Cl, where it will become the electron $[3, 1, 1, -\frac{1}{2}]$ , thus conserving charge, as there is an equal total number of electrons before and after the reaction.