The electrons hold onto the nucleus because of the magnetism and the electricity. <span />
KOH + HBr ---> KBr + H2O
0,3 moles of HBr ---in-------1000ml
x moles of HBr-------in------75ml
x = 0,0225 moles of HBr
according to the reaction: 1 mole of KOH = 1 mole of HBr
so
0,0225 moles of HBr = 0,0225 moles of KOH
0,0225 mole of KOH------in-----45ml
x moles of KOH -----------in------1000ml
x = 0,5 moles of KOH
answer: 0,5 mol/dm³ KOH (molarity)
Molar mass :
O2 = 31.99 g/mol
C5H12 = 72.14 g/mol
<span>C5H12 + 8 O2 = 5 CO2 + 6 H2O
</span>
74.14 g ----------------- 8 x 31.99 g
18 g -------------------- ? ( mass of O2)
18 x 8 x 31.99 / 74.14 =
4606.56 / 74.14 => 62.133 g of O2
hope this helps!
Answer:
Part a: The IR spectrum is not sufficient due to the similar radical group presence in both product and reactants.
Part b: Mass Spectrum data is required in addition to the IR data for confirming the presence of recrystallized product.
Part c: The additional data is consistent with the expectations as the data is in support of that.
Explanation:
Part a
Acetanilide has a characteristic IR peak at around 3100-3200 cm^-1 (N-H Stretching) and 1500-1680 cm^-1 (C=O Stretching). Since a similar radical group (
) is present in the 4-bromoacetanilide, thus it is difficult to affirm the presence of the product solely on the basis of IR spectrum.
Part b
Mass Spectral data will affirm the presence of recrystallized product with certainty.
Part c
4-bromoacetanilide will have 
peak at two points (213 & 215) corresponding to the two Bromine isotopes (79 & 81).
Also parent peak at 171 (=43) will be in 49:51 due to presence of Bromine atoms.
Answer:
the candle is still solid..................in this case, yes!
Explanation:
it is still solid because the molecules are packed together tighter than the molecules in a liquid or gas.
