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gogolik [260]
3 years ago
10

Is this virus real? i know it may not be but i wanna see your opinions.

Chemistry
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

what

Explanation:

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How should students prepare to use chemicals in the lab? Select one or more: Sort the lab chemicals in alphabetical order for qu
maksim [4K]

Answer:

Sort the lab chemicals in alphabetical order for quick access.

Become familiar with the chemicals to be used, including exposure or spill hazards.

Locate the spill kits and understand how they are used.

Explanation:

There are many chemicals in a laboratory hence they should be sorted out and arranged in alphabetical order so that theory can easily be identified and located whenever they are required.

The properties of each chemical should be known especially hazards connected to exposure or spill of the chemicals.

The students should also familiarize themselves with the contents of spill kits and how they are used.

7 0
3 years ago
Identify whether each compound is a straight chain, branched chain, or cycloalkane.
ladessa [460]

Answer:

the first one is branched, the second one is also branched and the third one is cycloalkane

5 0
2 years ago
How are the circulatory systems in animals and plants alike
yKpoI14uk [10]

Ok, so the circulatory system in plants and animals is like a method of transport. Both plants and animals use this to transport waste and nutrition.

-Agarvated

(hope this helps, have a great day!)

8 0
3 years ago
A 0.2 g sample of pyrolusite is analyzed for manganese content as follows. Add 50.0 mL of 0.1 M solution of ferrous ammonium sul
enyata [817]

Answer:

66.7%

Explanation:

The reaction for the titration of the excess ferrous ion is:

  • 5Fe⁺² + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O

We calculate the moles of Fe⁺² from the used moles of KMnO₄:

  • 0.02 M * 15.0 mL = 0.30 mmol KMnO₄
  • 0.3 mmol KMnO₄ * \frac{5mmolFe^{+2}}{1mmolKMnO_4} = 1.5 mmol Fe⁺²

Then we substract those 0.30 mmol from the original amount used:

  • 0.1 M * 50.0 mL = 5.0 mmol Fe⁺²
  • 5.0 - 1.5 = 3.5 mmol Fe⁺²

The reaction between ferrous ammonium sulfate and MnO₂ is:

  • 2Fe⁺² + MnO₂ + 4H⁺ → 2Fe³⁺ + Mn²⁺ + 2H₂O

So we convert those 3.5 mmol Fe⁺² that were used in this reaction to MnO₂ moles:

  • 3.5 mmol Fe⁺²  * \frac{1mmolMnO_2}{2mmolFe^{+2}}= 1.75 mmol MnO₂

Then we convert MnO₂ to Mn₃O₄, using the reaction:

  • 3MnO₂ → Mn₃O₄ + O₂
  • 1.75 mmol MnO₂ * \frac{1mmolMn_3O_4}{3mmolMnO_2} = 0.583 mmol Mn₃O₄

Finally we convert Mn₃O₄ moles to grams:

  • 0.583 mmol Mn₃O₄ * 228.82 mg/mmol = 133.40 mg Mn₃O₄

And calculate the percent

  • 0.2 g = 200 mg
  • 133.40 / 200 * 100% = 66.7%
5 0
3 years ago
You will start this experiment with 25 mg of the trans isomer. What is the percent yield if you obtain 5 mg of the cis isomer?
USPshnik [31]
Isomers have the same molecular formula but they only differ in structure. So, when trans isomer is converted to cis isomer, you would expect a total mass of 25 mg exactly. So, the percent yield would be:

Percent yield = 5 mg/25 mg * 100 = <em>20%</em>
8 0
3 years ago
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