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Vadim26 [7]
3 years ago
5

Rewrite with only sin x and cos x. cos 3x

Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0
\cos (3x)=4\cos^3 x-3\cos x
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Eunice buys dog bed with a listed price of $31. Eunice uses a sale that provides 30% off. What is the total
Pachacha [2.7K]

Answer:

21.70

Step-by-step explanation:

First find the discount

31 * 30%

31 *.30

9.3

Subtract from the original amount

31 - 9.3

21.70

3 0
3 years ago
Which relationship describes angles 1 and 2? Select each correct answer. A adjacent angles B complementary angles C vertical ang
Scrat [10]
The correct answer for this question is this one:
<span>- A adjacent angles
-D supplementary angles

The relationship that describes angle 1 and angle 2 is that they are adjacent angles -- at the same time they are also supplementary angles.</span>
Hope this helps answer your question and have a nice day ahead.
3 0
2 years ago
Read 2 more answers
Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a
evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1=\frac{1}{2} *PQ*RM

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=\frac{1}{2} *SR*PN

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=\frac{1}{2}*PQ*h

S2=\frac{1}{2}*SR*h

Adding them together, we get the area of the whole trapezoid:

S=S1+S2=\frac{1}{2} (PQ+SR)h,

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}

Simplifying, we have

=>A= \frac{ah+2b_{1+C} }{2}

Factoring we have,

=> A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2}  \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}

 But, a+ b_{1} + c  is equal to b_{2}, the longer base of our trapezoid.

Hence, A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}

We have discussed two ways by which we can derive area of a trapezoid.

Read to know more about Trapezoid

brainly.com/question/4758162?referrer=searchResults

#SPJ10

5 0
1 year ago
Write a subtraction problem involving regrouping that has ted reading 304 pages. Answer your question
kari74 [83]
How about this:

The book has 712 pages. Ted has already read 408 pages, so he has 304 left to read.
712 - 408 = 304

4 0
2 years ago
Will give BRAINEST
Svetlanka [38]
X-y=2 (*-2) --> -2x+2y=-4
2x+3y=14 
------------------
2x+3y=14 
 -2x+2y=-4
------------------
5y=10
y=2


4 0
3 years ago
Read 2 more answers
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