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Vadim26 [7]
3 years ago
5

Rewrite with only sin x and cos x. cos 3x

Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0
\cos (3x)=4\cos^3 x-3\cos x
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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil
Over [174]

Hello! :)

—————— ☆ ☆———————————————————————————-

Answer:

5.3 seconds

Step-by-step explanation:

The answer is 5.3 seconds because

If you solve this equation than you will see how it is 5.3 seconds.

Equation: h (t) = -16t ^ 2 + 48t + 190

Also if you graph it, the answer will be 5.3 seconds

—————— ☆ ☆————————————————————————————

Hope this helps! :)

By: BrainlyMember ^-^

Good luck!

3 0
3 years ago
Read 2 more answers
Find the measure of KM¯¯¯¯¯¯¯¯¯¯.
PilotLPTM [1.2K]

Answer:

12

Step-by-step explanation:

(whole secant) x (external part) =    (whole secant) x (external part)

( 7+x+2) * 7 = ( 6+8) * 6

Combine like terms

(9+x) *7 = 14*6

Distribute

63 +7x = 84

Subtract 63

63 +7x -63 = 84-63

7x =21

Divide by 7

7x/7 = 21/7

x = 3

KM = x+2+7

      = 3+2+7

      =12

6 0
3 years ago
Read 2 more answers
How do you solve this equation?
Ivenika [448]
To solve this question, what you would need to do is add 30 to both sides of the equation and then divide by 9, to find the solution.

You can check if it is correct by substituting the same value back into the original equation and seeing if the left hand side is equal to the right hand side.
7 0
3 years ago
Read 2 more answers
Solve by factoring: 2x2 - 5x - 12 = 0
Zepler [3.9K]

Step-by-step explanation:

2 {x}^{2}  - 5x - 12

2 {x}^{2}   - 8x  + 3x - 12

2x(x - 4) + 3(x - 4)

2x  + 3 = 0 \:  \: x - 4 = 0

x =  \frac{ - 3}{2}  \:  \: x =4

5 0
3 years ago
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Let’s look at another one of Homer’s rocket launches. It was launched from ground level with an initial velocity of 208 feet per
kozerog [31]

Answer:

Smax = 676 ft

the maximum altitude (height) the rocket will attain during its flight is 676 ft

Step-by-step explanation:

Given;

The height function S(t) of the rocket as;

S(t) = -16t2 + 208t

The maximum altitude Smax, will occur at dS/dt = 0

differentiating S(t);

dS/dt = -32t + 208 = 0

-32t +208 = 0

32t = 208

t = 208/32

t = 6.5 seconds.

The maximum altitude Smax is;

Substituting t = 6.5 s

Smax = -16(6.5)^2 + 208(6.5)

Smax = 676 ft

the maximum altitude (height) the rocket will attain during its flight is 676 ft

8 0
3 years ago
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