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Tanzania [10]
3 years ago
12

Find the radius of a circle whose circumference is 216 units, use 3.14 for π. r = 34.377 r = 34.395 r = 68.790

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

The value of radius is 34.395..

Step-by-step explanation:

The formula for finding the circumference of the circle is:

C=2πr.

Here we have given the values:

circumference = 216 units

π = 3.14.

r = ?

Substitute the values in the formula:

216 = 2(3.14)r

216=6.28r

Now divide both sides by 6.28.

We get,

216/6.28 = 6.28r/6.28

34.395=r

Thus the value of radius is 34.395...

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You have $1,500 to spend over a five month semester to cover your living expenses. In the first month, you spend $150 at restaur
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Step-by-step explanation:

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What's a simplified form of x-1+4+7x-3
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Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an
Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean \mu, standard deviation \sigma.

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

8 0
2 years ago
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