I'm not sure if I get what you mean, because I don't think I remeber what an area model is. But if it literally means making a model to describe the area, you could draw a square and put 84 on the length or the width and the o.24 on the other. Show that length times width = area. And then multiply. But if I am right, that's not what you are looking for, huh?
Answer:
Step-by-step explanation:
The origin (x,y) is (0,0)
If its moved four units right you must add 4 to the x coordinate giving you (4,0)
Then it is moved up by 5, so you must add 5 to the y coordinate giving you
(4,5)
Hey!
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First Equation:
2x + 3 = -7
2x + 3 - 3 = -7 - 3 (Subtract 7 to both sides)
2x = -10
2x/2 = -10/2 (Divide 2 to both sides)
x = -5
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Second Equation:
4.5x - 7 = 20
4.5x + (-7) + 7 = 20 + 7 (Add 7 to both sides)
4.5x = 27
4.5x/4.5 = 27/4.5 (Divide 4.5 to both sides)
x = 6
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Third Equation:
-3x + 7 = 28
-3x + 7 - 7 = 28 - 7 (Subtract 7 to both sides)
-3x/-3 = 21/-3 (Divide -3 to both sides)
x = -7
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Answers:
2x + 3 = -7 → x = -5
4.5x - 7 = 20 → x = 6
-3x + 7 = 28 → x = -7
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Hope This Helped! Good Luck!
Note: The equations written in this questions are not appropriately expressed, however, i will work with hypothetical equations that will enable you to solve any problems of this kind.
Answer:
For the system of equations to be unique, s can take all values except 2 and -2
Step-by-step explanation:

![\left[\begin{array}{ccc}2s&4\\2&s\end{array}\right] \left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right] = \left[\begin{array}{ccc}-3 \\6 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2s%264%5C%5C2%26s%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%20%5C%5C6%20%5Cend%7Barray%7D%5Cright%5D)
For the system to have a unique solution, 
