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shutvik [7]
3 years ago
15

Two technicians are discussing refrigerant lines. Technician A says that line connections must be tight but not so tight that ai

r can't get through. Technician B says that all connection O-rings have to be replaced when retrofitting a system to R-134a. Who is correct?
Chemistry
2 answers:
lbvjy [14]3 years ago
4 0
B is right...............
..
lions [1.4K]3 years ago
4 0

Answer:

The correct answer is: technician B, all connection O-rings have to ve replaced when retrofitting a system to R-134a.

Explanation:

When we have a refrigerant line, the refrigerant is used through a refrigeration cycle. Refrigerant should pass in a physical process of transformation, it should be pure, avoid another kind of phenomena.

When we are retrofitting a system to R-134a, it is thus necessary to change all connection O-rings. In that way, we can prevent the refrigerant of crossed contamination with other refrigerants or substances.

Let's analyze the opposite situation, if we do not change the O-rings and we change the refrigerant, probably there will be a few previous substances, which can react, or create other phenomena when they undergo the refrigeration cycle with the R-134 a. We have to avoid this situation. 

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The heat of vaporization for benzaldehyde is 48.8 kj/mol, and its normal boiling point is 451.0 k. use this information to deter
user100 [1]

Answer:

The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

Explanation:

  • To solve this problem, we use Clausius Clapeyron equation: ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂).
  • The first case: P₁ = 1 atm = 760 torr and T₁ = 451.0 K.
  • The second case: P₂ = <em>??? needed to be calculated</em> and T₂ = 61.5 °C = 334.5 K.
  • ΔHvap = 48.8 KJ/mole = 48.8 x 10³ J/mole and R = 8.314 J/mole.K.
  • Now, ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂)
  • ln(760 torr /P₂) = (48.8 x 10³ J/mole / 8.314 J/mole.K) (1/451 K - 1/334.5 K)
  • ln(760 torr /P₂) = (5869.62) (-7.722 x 10⁻⁴) = -4.53.
  • (760 torr /P₂) = 0.01075
  • Then, P₂ = (760 torr) / (0.01075) = 70691.73 torr.

So, The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

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