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zzz [600]
2 years ago
10

A substance has a molecular formula of C8H10N4O2

Chemistry
1 answer:
Nutka1998 [239]2 years ago
5 0

The empirical formula of a substance = C₄H₅N₂O

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

<em>(empirical formula) n = molecular formula  </em>

((empirical formula)n=C₈H₁₀N₄O₂

divide by 2 :

(C₄H₅N₂O)₂=C₈H₁₀N₄O₂

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Which of the following is a heterogeneous mixture?
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A heterogeneous mixture is a mixture that it's components can be easily seen and separated. 

c. a jar of mixed nuts

3 0
3 years ago
Read 2 more answers
How many grams of iron are needed to combine with 24.9 g of 0 to make Fe203?
Pavlova-9 [17]

Answer:

Explanation:

Here's where all that equation balancing is going to come into use. Since the main object of the question is not the equation, I'm just going to balance it and use it.

4Fe + 3O2 ====> 2Fe2O3

Step One

Find the number of mols of O2 in 24.9 grams of O2

1 mol O2 = 2*16 = 32 grams

x mol O2 = 24.9 grams               Cross multiply

32x = 24.9 * 1                               Divide by 32

x = 24.9/32

x = 0.778 moles of O2

Step Two

Type the findings under the balanced equations parts. Solve for the number of moles of Fe

4Fe + 3O2 ====> 2Fe2O3

x          0.778

Step Three

Set up the proportion

4/x = 3/0.778            Cross multiply

Step Four

Solve the proportion moles of Fe

4*0.778 = 3x              

3.112   =    3x                      Divide by 3

3.112/3 = 3x/3

x = 1.037 moles of Fe

Step Five

Find the mass of Fe

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x = 56*1.037

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4 0
3 years ago
1.Convert 2.37 moles of Al(NO3)3 to grams.. Single choice.
aleksley [76]

Answer:

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Explanation:

1.

g = moles x molar mass = 2.37 x 212.996 = 504.8 g Al(NO3)3

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2.

moles = mass : molar mass = 456.89: 32 = 14.3 moles O2

7 0
3 years ago
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xxTIMURxx [149]

Answer:

To avoid spattering

Explanation:

If we are heating a hydrate to drive off the water of crystallization, we must initially heat the hydrate gently, at a lower temperature and then more strongly only after most of the water has been driven off in order to to prevent spattering.

Since we obtain the amount of water by the mass difference, Spattering  decreases the mass of water obtained and ultimately results in a lower percent of water being calculated for the hydrate.

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