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suter [353]
3 years ago
14

Which part of the water cycle would follow step C in the diagram shown?

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Evaporation

Explanation:

From point C to D, this is a phase change from liquid to gas and it would be depicted by evaporation.

The water cycle presents the transformation of water from one form to another on our planet.

  • From Point A to B in which water falls from clouds is a precipitation step.
  • Point B to Point C is the step in which surface water runs into lakes.
  • Point C to Point D where water turns to gas in the atmosphere is evaporation.
  • The from point a D back to A is condensation.

Learn more:

Evaporation brainly.com/question/10972073

#learnwithBrainly

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How are dwarf planets and major planets similar? (Choose all that apply)
Lina20 [59]

Answer:

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Explanation:

6 0
3 years ago
In a reaction of a potential new fuel, it is found that when 2.81 moles of the fuel combusts, 1,612 kJ of energy is released. Wh
Tema [17]

Answer:

-573.67

Explanation:

whenever energy is released in a chemical reaction, we would then expect the delta H of the reaction to be negative because the reaction is an exothermic reaction.

now we have that 2.81 moles of fuel when it combusts would releases 1612kJ of energy

thus, 1 mole will release 1612/2.81 = -573.67kJ of heat

Therefore the delta H of the reaction = -573.67 kJ/mol

3 0
3 years ago
How much energy do individual photons of 470 nm light have
IceJOKER [234]
<h3>Answer:</h3>

4.227 × 10^-19 Joules

<h3>Explanation:</h3>

Energy of a photon of light is calculated by the formula;

E = hf, where h is the plank's constant, 6.626 × 10^-34 J-s and f is the frequency.

But, f = c/λ

Where, c is the speed of light (2.998 × 10⁸ m/s), and λ is the wavelength.

Given the wavelength is 470 nm or 4.7 × 10^-7 m

Therefore;

E = hc/λ

  = (6.626 × 10^-34 J-s × 2.998 × 10^8 m/s) ÷ 4.7 × 10^-7 m

  = 4.227 × 10^-19 Joules

Therefore, the energy of a photon with 470 nm is 4.227 × 10^-19 Joules

3 0
4 years ago
Which element would you expect to be more metallic?<br> (a) S or Cl (b) In or Al (c) As or Br
Natalija [7]

Explanation:

When we move across a period from left to right then there will occur an increase in electronegativity and also there will occur an increase in non-metallic character of the elements.

As sulfur (S) is a group 16 element and chlorine (Cl) is a group 17 element. Hence, sulfur (S) is more metallic in nature than chlorine.

This means that chlorine (S) is less metallic than chlorine (Cl).

Both indium (I) and aluminium (Al) are group 13 elements. And, when we move down a group then there occur an increase in non-metallic character of the elements. As indium belongs to group 13 and period 5 whereas aluminium belongs to group 13 and period 3.

Therefore, aluminium (Al) is more metallic than indium (In).

Arsenic (Ar) is a group 15 element and bromine (Br) is a group 17 element. Therefore, arsenic is more metallic than bromine.

4 0
4 years ago
Why is it so difficult
Sergeeva-Olga [200]
Because teachers don’t really understand it all that well themselves so they can’t teach it effectively
5 0
2 years ago
Read 2 more answers
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