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dlinn [17]
3 years ago
8

If abx - 5 = 0, what is x in terms of a and b?

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
6 0
Here we want to have x on one side of equation so,
we put number 5 on right side of equation:
abx=5
then we divide both sides by ab to obtain x on left side:
Result:
x=<u />\frac{5}{ab}
LenaWriter [7]3 years ago
5 0
abx - 5 = 0

abx - 5 +5= 0+5

abx=5

\frac{abx}{ab} = \frac{5}{ab}

x= \frac{5}{ab}
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Answer:

W=1000C/tc

Step-by-step explanation:

First multiply both side 1000: 1000C=Wtc

Divide both side by tc: 1000C/tc=W (t, c ≠0)

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The perimeter of the triangle with the sides measuring 15 inches, 18 inches, and 7 inches is 40 inches. If you wanted to constru
Arlecino [84]
The results in the question conclude that it is an isosceles triangle so your answer can vary; for example, your could be 10, 22, 18 which would make the perimeter 50 like the question states. So your answer will vary anyways you just have to remember that it is an isosceles triangle so all three sides will be a different length.
7 0
3 years ago
HELP ASAP!!! PLEASE CHECK ALL OF THEM!
pochemuha

Answer:

2.

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

+

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

3.

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

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= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

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Step-by-step explanation:

8 0
3 years ago
Solve.
lions [1.4K]

Answer:

b=9,a=12

Step-by-step explanation:

I solved by substitution:

b = 3/4a  ---> plug this into the other equation

a + b = 21   is now    a + 3/4a = 21

Reduce: 7/4a = 21

a = 12

Now solve for b:

b=3/4a is now b=3/4(12)

b=9

6 0
3 years ago
Read 2 more answers
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