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ivanzaharov [21]
3 years ago
10

a partial grassland food web is shown. Which of the following best describes a relationship in this grassland.

Chemistry
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

The answer is "Upland sandpipers are primary and secondary consumers because they eat grasses and grasshoppers".

Explanation:

The limited farmland nutrition web, that reveals better which Upland sandpipers were main and secondary customers in this farmland since they eat grass with grasshoppers.  

  • It also eat butterflies, bricks, shrimps, mollusks, worms, and nematodes, throughout contrast to bugs, which sandpipe gathers seed of hay, plants, conifers, and rice, rye, or strawberries.
  • Highlands dragonflies sometimes assemble in recently burnt fields with such a wealth of squirrels.
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How many grams of Al will be deposited from molten AlCl3 by a current of 15.0 amp flowing for 24.0 hr ( 1 Faraday = 96500 C)
zimovet [89]

Answer:

121 aprox.

Explanation:

mass/molar mass = Q/CF

where mass=?

molar mass of Al=27

Q=It = 15×24×60×60

C=3

F=96500

7 0
4 years ago
Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of –7.2°C. Bromine can be classified as a
andreev551 [17]

Answer:

Pure substance.

Explanation:

7 0
3 years ago
What parts of a circuit is a conductor?
netineya [11]

Answer:

copper

Explanation:

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3 0
3 years ago
In the reaction between Lithium Sulfate and an excess of Lead (II) Nitrate, how many molecules of Lithium Nitrate can be expecte
siniylev [52]

Answer:

1.46x10^{23}molecules \ LiNO_3

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Li_2SO_4 + Pb(NO_3)_2 \rightarrow PbSO_4+2LiNO_3

Thus, since lead (II) nitrate is in excess, we can directly compute the moles of lithium nitrate by applying the 1:2 molar ratio between them in the chemical reaction as well as the molar mass of Lithium Sulfate that is 110 g/mol for the stoichiometric shown below factor:

n_{LiNO_3}=13.3gLi_2SO_4*\frac{1molLi_2SO_4}{110gLi_2SO_4} *\frac{2molLiNO_3}{1molLi_2SO_4} =0.242molLiNO_3

Finally, by using the Avogadro's number we are able to compute the molecules:

0.242molLiNO_3*\frac{6.022x10^{23}molecules\ LiNO_3}{1mol}=1.46x10^{23}molecules \ LiNO_3

Best regards.

5 0
4 years ago
Read 2 more answers
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Red blood cells carry oxygen throughout the human body
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4 years ago
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