Answer:
56.24g
Explanation:
To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).
number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23
n = 4.45/6.02 × 10^(23 - 23)
n = 0.74 × 10^0
n = 0.74moles.
Using the formula below to find the mass of N2O3;
mole = mass ÷ molar mass
Molar mass of N2O3 = 14(2) + 16(3)
= 28 + 48
= 76g/mol
mass = mole × molar mass
Mass = 0.74 × 76
Mass = 56.24g
Answer:- 1337 g
Solution:- For mathematical operations we use PEMDAS. P stands for parenthesis off, E stands for exponents, M stands for multiplication, D stands for division, A stands for addition and S stands for subtraction. All the mathematical operations are done in this sequence.
What we have given in the problem is, 1210.0 g + 157.22 g - 30. g
Here we have addition and subtraction. As per the law, we will do addition first. In addition and subtraction we go with least number of decimal places.
1210.0 has one decimal place where as 157.22 has two decimal places, since the first number has least decimal places(one decimal place), the answer should also have only one decimal place.
1210.0 g + 157.22 g = 1367.2 g
Now, we will do subtraction. 30. does not have any decimal place and so on subtraction the final answer must not have any decimal places.
1367.2 g - 30. g = 1337 g
So, the final answer is 1337 g.
11.
c, because the object is not in direct contact to anything with gravity
<u>Answer:</u>
CHCl3 has dipole-dipole interactions.
<u>Explanation:</u>
Trichloromethane has a electric dipole moment permanently pointing along the line parallel with the Hydrogen carbon axis.Dipole-dipole interactions are said to be intermolecular force of attractions that is formed from two permanent dipoles interacting.
These type of interactions are occurring when one of the partially charged formed molecule are being attracted to an opposite partially charged molecule nearby . The molecules align in a state that the positive end of one of the molecule gets interacting with the negative end of the another molecule.