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3 years ago

GCF OF 16 20 and 24 .....

Mathematics

2 answers:

diamong [38]3 years ago

6 0

Answer:4

Step-by-step explanation:

16: 1,2,4,16

20:1,2,4,5,10,20

24: 1,2,3,4,6,8,12,24

The greatest common factor is four

Gemiola [76]3 years ago

3 0

Answer:

the gcf of 16, 20, and 14 is 4

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Edward can run 1/2 mile in 300 seconds what is edwards unit rate

Vilka [71]

Rate/ speed = distance / time;
= 1/2mile / 300 seconds;
= 0.001666666..... mile/second

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3 years ago

The ratio of the number of volleyball to the number of basketballs in the P.E room is 4:7 .there are 21 basketballs . How many v

densk [106]

Let volleyball be v and let basketball be b.

v : b = 4 : 7, b = 21

v : 21 = 4 : 7

v/21 = 4/7

7*v = 4*21

v = 4*21/7

v = 4*3

v = 12

Volleyballs are 12

Hope this helps.

8 0

3 years ago

In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :

Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

$\angle DIH\cong \angle EGH$ as alternate interior angles;
$\angle DHI\cong \angle GHE$ as vertical angles;
$DH\cong HE$ because point H bisects segment DE (given).

Thus,

$\triangle DIH\cong \triangle EGH$ by AAS postulate

4 0

3 years ago

A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par

ElenaW [278]

The equation of the central street PQ is -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

$-7x+3y=-21.5$

Convert it to the general form given below:

$\rm y=mx+c$

$\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x$ or

$\rm y = \frac{7}{3}x-\frac{21.5}{3}$

$m = \frac{7}{3}$ (Slope of AB line)

For the slope(m') of the PQ line:

$\rm m'=-\frac{1}{m}$ ( because AB and PQ are perpendicular to each other)

$\rm m' = -\frac{3}{7}$

We know the:

$\rm (y-y')=m'(x-x')$

Where (x', y') = (7, 6), we get:

$\rm (y-6)=-\frac{3}{7} (x-7)$

$\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63$

$\rm -1.5x-3.5y=-31.5$ (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is -1.5x - 3.5y = -31.5

Learn more about the straight line.

brainly.com/question/3493733

6 0

1 year ago

Help me. I need help on multiply decimal with exponents

AleksAgata [21]

Answer:

Step-by-step explanation:

for the first 2 questions 3.04 x 10^2 you would move the decimal over 2 places and 0.304 x 10^4 just move the decimal over4 places and you have your answer

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3 years ago