All categories

3 years ago

Non-metals tend to

Chemistry

1 answer:

IgorLugansk [536]3 years ago

5 0

Answer:

gain, negative

Explanation:

Non-metals tend to GAIN

electrons to be come NEGATIVE

ions.

You might be interested in

4 AlF3 + 3 O2 ----------> 2Al2O3 + 6 F2

anyanavicka [17]

Explanation:

6 F2------->4 AlF3

F2-----------> 4/6 AlF3

8.25 F2 ---------> 4×8.25/6 AlF3

so 5.5 moles

8 0

3 years ago

how many moles of water are in 1.23 x 10^18 water molecules? I need the answer in scientific notation ?

Ann [662]

Answer:

Moles=2.04×10^(-6)

Explanation:

No. Of moles=no. Of particles/ Avogadro's no

(Where no. Of particles may be atoms molecules or compounds)

Moles=1.23×10^18/6.022×10^23

Moles=0.204×10^(-5)

Moles=2.04×10^(-6)

8 0

3 years ago

Air at 293 K and 750 mm Hg pressure has a relative humidity of 80%. What is its percent humidity? The vapour pressure of water a

Mekhanik [1.2K]

Answer : The correct option is, (c) 79.62

Explanation :

The formula used for percent humidity is:

$\text{Percent humidity}=\text{Relative humidity}\times \frac{p-p^o_v}{p-p_v}\times 100$ ..........(1)

The formula used for relative humidity is:

$\text{Relative humidity}=\frac{p_v}{p^o_v}$ ...........(2)

where,

$p_v$ = partial pressure of water vapor

$p^o_v$ = vapor pressure of water

p = total pressure

First we have to calculate the partial pressure of water vapor by using equation 2.

Given:

$p=750mmHg$

$p^o_v=17.5mmHg$

Relative humidity = 80 % = 0.80

Now put all the given values in equation 2, we get:

$0.80=\frac{p_v}{17.5mmHg}$

$p_v=14mmHg$

Now we have to calculate the percent humidity by using equation 1.

$\text{Percent humidity}=0.80\times \frac{750-17.5}{750-14}\times 100$

$\text{Percent humidity}=79.62\%$

Therefore, the percent humidity is 79.62 %

4 0

3 years ago

How do the ions in metals behave?

nikdorinn [45]

A metal ion is a type of atom compound that has an electric<span> charge. </span>Such<span> atoms willingly lose electrons in order to build positive ions called cations.</span>

4 0

3 years ago

How many grams of NaCl (molecular weight = 58.4 g mole-1) would you dissolve in water to make a total volume of 500 mL of soluti

kolezko [41]

Given :

Volume , V = 500 mL .

Molarity , M = 0.5 M .

Molecular mass of NaCl is $58.4\ g/mole$ .

To Find :

How many grams of NaCl is required .

Solution :

Let , NaCl required is x gram .

Molarity is given by :

$M=\dfrac{\text{Number of moles}}{\text{Volume (in liters) }}\\\\M=\dfrac{m}{M\times V}\\\\0.5=\dfrac{x}{58.4\times 0.5}\\\\x=0.5^2\times 58.4\ g\\\\x=14.6\ g$

Hence , this is the required solution.

6 0

2 years ago