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Vilka [71]
3 years ago
10

How many atoms are in 52.3 g of calcium ?

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
8 0

Explanation:

one mole contains Avogadro number of particles

So,

40g( the atomic mass) contains 6.023× 10^23 atoms.

so 1 g contains 40÷(6.023×10^23)

so, 52.3 g contains (40×52.3) ÷6.023×10^23

= 3.47× 10^-21

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A student decided to research primate psychology for their science project. They measured how long it took gorillas to adapt to
Gwar [14]

Answer: the answer is  D im pretty sure

Explanation:

3 0
3 years ago
How many moles is 22.4 liters of oxygen gas at standard temperature and pressure represent
makkiz [27]

Answer:

So 1 mole

Explanation:

PV = nRT

P = Pressure atm

V = Volume L

n = Moles

R = 0.08206 L·atm·mol−1·K−1.

T = Temperature K

standard temperature = 273K

standard pressure = 1 atm

22.4 liters of oxygen

Ok so we have

V = 22.4

P = 1 atm

PV = nRT

n = PV/RT

n = 22.4/(0.08206 x 273)

n  = 22.4/22.40

n = 1 mole

7 0
3 years ago
The molar mass is determined by measuring the freezing point depression of an aqueous solution. A freezing point of -5.20°C is r
Dima020 [189]

Answer:

The empirical formula is C2H4O3

The molecular formula is C4H8O6

The molar mass is 152 g/mol

Explanation:

The complete question is: An unknown compound contains only carbon, hydrogen, and oxygen. Combustion analysis of the compound gives mass percents of 31.57% C and 5.30% H. The molar mass is determined by measuring the freezing-point depression of an aqueous solution. A freezing point of -5.20°C is recorded for a solution made by dissolving 10.56 g of the compound in 25.0 g water. Determine the empirical formula, molar mass, and molecular formula of the compound. Assume that the compound is a nonelectrolyte.

Step 1: Data given

Mass % of Carbon = 31.57 %

Mass % of H = 5.30 %

Freezing point = -5.20 °C

10.56 grams of the compound dissolved in 25.0 grams of water

Kf water = 1.86 °C kg/mol

Step 2: Calculate moles of Carbon

Suppose 31.57% = 31.57 grams

moles C = mass C / Molar mass C

moles C = 31.57 grams / 12.0 g/mol = 2.63 moles

Step 3: Calculate moles of Hydrogen:

Moles H = 5.30 grams / 1.01 g/mol

moles H = 5.25 moles

Step 4: Calculate moles of Oxygen

Moles O = ( 100 - 31.57 - 5.30) / 16 g/mol

Moles O = 3.95 moles

Step 5: We divide by the smallest number of moles

C: 2.63 / 2.63 = 1 → 2

H: 5.25/2.63 = 2 → 4

O: 3.95/ 2.63 = 1.5 → 3

The empirical formula is C2H4O3

The molar mass of the empirical formula = 76 g/mol

Step 6: Calculate moles solute

Freezing point depression = 5.20 °C = m * 1.86

m = 5.20 / 1.86

m = 2.80 molal = 2.80 moles / kg

2.80 molal * 0.025 kg = 0.07 moles

Step 7: Calculate molar mass

Molar mass = mass / moles

Molar mass = 10.56 grams / 0.07 moles

Molar mass = 151 g/mol

Step 8: Calculate molecular formula

151 / 76 ≈  2

We have to multiply the empirical formula by 2

2*(C2H4O3) = C4H8O6

The molecular formula is C4H8O6

The molar mass is 152 g/mol

6 0
3 years ago
Given the equation representing a system at equilibrium:
polet [3.4K]
I think the one that cause the equilibrium to shift would be :
3. adding a noble gas
Adding the noble gas will add more concentration to the KNO3, which will create different amount of equilibrium

hope this helps
3 0
3 years ago
What is the volume of 8.7 * 10 ^ 23 molecules of chlorine gas (Cl 2 ) ?
Mariana [72]

Answer:

32.3 dm³

Explanation:

Data given:

no. of molecules of Cl₂ = 8.7 x 10²³

Volume of chlorine gas (Cl₂) = ?

Solution:

First we have to find number of moles

For this formula used

    no. of moles = no. of molecules / Avogadros number

    no. of moles = 8.7 x 10²³ / 6.022 x 10²³

    no. of moles = 1.44 moles

Now we have to find volume of the gas

for this formula used

                      no. of moles = volume of gas / molar volume

molar volume = 22.4 dm³/mol

Put values in above equation

                 1.44 moles = volume of Cl₂ gas / 22.4 dm³/mol

rearrange the above equation

                 volume of Cl₂ gas = 1.44 moles x 22.4 dm³/mol

                volume of Cl₂ gas =  32.3 dm³

8 0
3 years ago
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