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emmasim [6.3K]
3 years ago
15

If you see trapped bubbles ,you have to tap the cover slip using a

Chemistry
1 answer:
trapecia [35]3 years ago
5 0

Answer:

?.............?...............

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As a gas changes to a solid, energy<br> A. is not used.<br> B. is released.<br> C. is absorbed.
pogonyaev

Answer:

B

Explanation:

Energy is released, when a gas changes to solid

7 0
3 years ago
Determine the relative amounts (in terms of volume fractions) for a 15 wt% sn-85 wt% pb alloy at 100°c. the densities of tin an
nikdorinn [45]
Volume fraction = volume of the element / volume of the alloy

Volume = density * mass

Base: 100 grams of alloy

mass of tin = 15 grams

mass of lead = 85 grams

volume = mass / density

Volume of tin = 15g / 7.29 g/cm^3 = 2.06 cm^3

Volume of lead = 85 g / 11.27 g/cm^3 = 7.54 cm^3

Volume fraction of tin = 2.06 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.215

Volume fraction of lead = 7.54 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.785

As you can verify the sum of the two volume fractions equals 1: 0.215 + 0.785 = 1.000
6 0
3 years ago
Which two particles are found in the center of an atom?
seraphim [82]

Answer:

B) Protons and Neutrons

Explanation:

In every atom, there is a Nucleus which contains protons and Neutrons. Protons being positive and Neutrons not having a charge (neutral).  

6 0
3 years ago
Read 2 more answers
You have 363 mL of a 1.25M potassium chloride solution, but you need to make a 0.50M potassium chloride solution. How many milli
maxonik [38]

Answer:- 544.5 mL of water need to be added.

Solution:- It is a dilution problem. The equation used for solving this type of problems is:

M_1V_1=M_2V_2

where, M_1 is initial molarity and  M_2 is the molarity after dilution. Similarly,  V_1 is the volume before dilution and  V_2 is the volume after dilution.

Let's plug in the values in the equation:

1.25M(363mL)=0.50M(V_2)

V_2=\frac{1.25M(363mL)}{0.50M}

V_2=907.5mL

Volume of water added = 907.5mL - 363mL  = 544.5 mL

So, 544.5 mL of water are need to be added to the original solution for dilution.

3 0
3 years ago
Ca+Cl2--&gt;CaCl2 Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.
kompoz [17]

Answer:

Oxidation half

Ca -----> Ca2+ +2elecyrons

Reduction half

Cl2 + 2electrons ------> 2Cl-

Explanation:

8 0
3 years ago
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