Assume an original volume of blood of one deciliter (100 ml). if 5 ml of oxygen diffuses into the blood, 100 ml will be its final volume.
A tissue is made up of white blood cells, platelets, red blood cells, and other elements suspended in a liquid. Blood transports waste away and delivers nutrients and oxygen to the tissues. The entire amount of fluid moving through the heart's arteries, capillaries, veins, venules, and chambers is referred to as blood volume. Red blood cells (erythrocytes), white blood cells (leukocytes), platelets, and plasma are the elements that give blood volume.
The amount of water and sodium ingested, expelled by the kidneys into the urine, and lost through the digestive system, lungs, and skin determines blood volume. The amounts of salt and water that are consumed and excreted vary greatly.
To know more about blood volume refer to: brainly.com/question/7313563
#SPJ4
<span>It affects only one chemical reaction</span>
Answer:
Explanation:
YES BECAUSE YE SIS YES WHEN YES=![\sqrt{x} x^{2} x^{2} \neq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20x%5E%7B2%7D%20x%5E%7B2%7D%20%5Cneq%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D)
GAMER MOMENT FROM LUIGI FOR⇔![\sqrt{x} x^{2} x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \alpha \alpha \alpha x_{123} \frac{x}{y} \pi \neq \geq \leq \\ \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx x^{2} \sqrt{x} \sqrt{x} \\](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20x%5E%7B2%7D%20x%5E%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%5Calpha%20%5Calpha%20%5Calpha%20x_%7B123%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Cpi%20%5Cneq%20%5Cgeq%20%5Cleq%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20x%5E%7B2%7D%20%5Csqrt%7Bx%7D%20%5Csqrt%7Bx%7D%20%5C%5C)
Answer:
V₂ = 2.91 L
Explanation:
Given data:
Initial volume = 3.50 L
Initial temperature = 90.0°C (90+273 = 363 K)
Final temperature = 30.0 °C ( 30 +273 = 303 K)
Final volume = ?
Solution:
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
V₁/T₁ = V₂/T₂
3.50 L / 363 K) = V₂ / 303 K)
V₂ = 0.0096 L/K × 303 K
V₂ = 2.91 L
