A train starts from rest and accelerates uniformly until it has traveled 5.6 km and acquired a velocity of 42 m/s. What is the a
pproximate acceleration of the train during this time?
1 answer:
Answer:
0.16 m/s²
Step-by-step explanation:
Given:
Δx = 5600 m
v₀ = 0 m/s
v = 42 m/s
Find: a
v² = v₀² + 2aΔx
(42 m/s)² = (0 m/s)² + 2a (5600 m)
a = 0.16 m/s²
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