Question

A train starts from rest and accelerates uniformly until it has traveled 5.6 km and acquired a velocity of 42 m/s. What is the approximate acceleration of the train during this time?

Answer 1

Answer:

0.16 m/s²

Step-by-step explanation:

Given:

Δx = 5600 m

v₀ = 0 m/s

v = 42 m/s

Find: a

v² = v₀² + 2aΔx

(42 m/s)² = (0 m/s)² + 2a (5600 m)

a = 0.16 m/s²