Answer: The required common ratio of the given geometric sequence is
Step-by-step explanation: We are given to find the common ratio of the following geometric sequence :
16, 24, 36, 54, . . .
We know that
the common ratio of a geometric sequence is the ratio of any term to its preceding term.
For the given sequence, we have
a(1) = 16, a(2) = 24, a(3) = 36, a(4) = 54, . . .
So, we get
Thus, the required common ratio of the given geometric sequence is
Answer:
Step-by-step explanation:
Angle <em>b</em> and 135° form a <em>linear pair</em>, so when summing them up to 180°, you will have 45° left over:
Now, by the <em>Vertical</em><em> </em><em>Angles</em><em> </em><em>Theorem</em>, angle <em>a</em> and 70°, in this case, are to be in <u>congruence</u> with each other, so you have that.
Now you must find the the measure of angle <em>c</em> sinse you have already found the measure of two angles already:
I am joyous to assist you at any time.
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Answer:
y = -3x^2 +3x +6
Step-by-step explanation:
For roots p and q, the equation can be written as ...
y = a(x -p)(x -q)
The value of 'a' must be determined so that the product <em>apq</em> is equal to the y-intercept. One could say that the formula is ...
y = (y-intercept)/(pq)·(x -p)(x -q)
For your given values of p = 2, q = -1, y-intercept = 6, this becomes ...
y = 6/(2(-1))(x -2)(x +1)
y = -3(x^2 -x -2) . . . . . simplifying a bit
y = -3x^2 +3x +6
