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3 years ago

Simplify. Remove all perfect squares from inside the square root.

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

3 0

Answer:

2x²√13

Step-by-step explanation:

√52x⁴ = √4×13×x⁴ = 2x²√13

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Help I'll give you 100 points

Dvinal [7]

✏ Answer:

$y=-9$

Step-by-step explanation:

$2-\frac{1}{8}y=11+\frac{7}{8}y$

➠ Subtract 2 from both sides:-

 $2-\frac{1}{8}y-2=11+\frac{7}{8}y-2$

$-\frac{1}{8}y=\frac{7}{8}y+9$

➠ Subtract 7/8y from both sides:-

 $-\frac{1}{8}y-\frac{7}{8}y=\frac{7}{8}y+9-\frac{7}{8}y$

$-y=9$

➠ Divide both sides by -1:-

 $\frac{-y}{-1}=\frac{9}{-1}$

$y=-9$

OAmalOHopeO

✎--------------------------

7 0

2 years ago

Read 2 more answers

What is the equation of the line of best fit for the following data? Round the slope and y-intercept of the line to three decima

Nadusha1986 [10]

Answer:

Step-by-step explanation:

it is really simple if you think about it or maybe I'm wrong

8 0

2 years ago

Read 2 more answers

The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)

Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores and D = difference between both

So, $\mu_A$ = Population mean for the math scores

$\mu_B$ = Population mean for the writing scores

Let $\mu_D$ = Difference between the population mean for the math scores and the population mean for the writing scores.

Null Hypothesis, $H_0$ : $\mu_A = \mu_B$ or $\mu_D$ = 0

Alternate Hypothesis, $H_1$ : $\mu_A \neq \mu_B$ or $\mu_D \neq$ 0

Hence, Test Statistics used here will be;

$\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ where, Dbar = Bbar - Abar

$s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$

n = 12

Student Math scores (A) Writing scores (B) D = B - A

1 540 474 -66

2 432 380 -52

3 528 463 -65

4 574 612 38

5 448 420 -28

6 502 526 24

7 480 430 -50

8 499 459 -40

9 610 615 5

10 572 541 -31

11 390 335 -55

12 593 613 20

Now Dbar = Bbar - Abar = 489 - 514 = -25

Bbar = $\frac{\sum B_i}{n}$ = $\frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}$ = 489

Abar = $\frac{\sum A_i}{n}$ = $\frac{540+432+528+574+448+502+480+499+610+572+390+593}{12}$ = 514

∑ $D_i^{2}$ = 22600 and $s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$ = $\sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} }$ = 37.05

So, Test statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$

= $\frac{-25 - 0}{\frac{37.05}{\sqrt{12} } }$ follows $t_1_1$ = -2.34

Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0

3 years ago

Find the missing number in the pattern:

zhenek [66]

Answer:

The pattern is that they are multiplying by -3 every time. 81*-3 = -243

4 0

2 years ago

9/x+7 = 4 i need the answer for my homework, please help x

Pachacha [2.7K]

Your answer is Answer:
x = -3

4 0

2 years ago

Simplify. Remove all perfect squares from inside the square root. ​

Simplify. Remove all perfect squares from inside the square root.