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3 years ago

What type of ossification occurs to form an immovable joint

Chemistry

1 answer:

ipn [44]3 years ago

5 0

Answer:

The type of ossification that occurs is the endomembrane or endochondral.

Explanation:

In this type of joints called SYNARTROSIS, there is no intermediate formation of ligaments or cartilage, with which the bone does not grow from a cartilage ossification, but from undifferentiated cells that will calcify and form bone cells and the main bone units that are the OSTEONAS. The bones that present this type of joints are the skull, in the area of the temporal bone (Temporary Suture) that grow abruptly throughout life and by mechanisms different from those bones that present a joint with movement.

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Calculate the density of helium if a balloon with a capacity of 5.00 L holds 0.890 g.

liubo4ka [24]

Answer:

Explanation:

Density is m/V. Also, 1 liter = 1000 $cm^3$ . So, we get 0.890/(5*1000) = $1.78*10^{-4}$ g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.

5 0

3 years ago

Properties of noble gases

ElenaW [278]

They are odourless, colourless monatomic gases with full outer shells

8 0

2 years ago

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Several bird species feed is a certain species of tree. Each bird species feeds in a different part of the tree. Which statement

Fofino [41]

Answer:

They have adapted to different niches.

Explanation:

due to competition

8 0

2 years ago

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How many moles of water are in a beaker with 50 mL?

tatiyna

Answer:

Number of moles = 2.8 mol

Explanation:

Given data:

Number of moles of water = ?

Volume of water = 50 mL

Density of water = 1.00 g/cm³

Solution:

1 cm³ = 1 mL

Density = mass/ volume

1.00 g/mL = mass/ 50 mL

Mass = 1.00 g/mL× 50 mL

Mass = 50 g

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 50 g / 18 g/mol

Number of moles = 2.8 mol

5 0

3 years ago

3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh

TiliK225 [7]

Answer:

$n_{C_6H_{10}}=0.03molC_6H_{10}$

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

$n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}$

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

$m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}$

Even thought, the volume could be also computed by using its density:

$V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}$

Best regards.

4 0

2 years ago

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