B, C, D are compounds, while A and E are just element stand-alones.
Answer:0.86
Explanation:
A mixture of methane gas, CH4(g), and pentane gas, C5H12(g), has a pressure of 0.5922 atm when placed in a sealed container.Lets suppose initially partial pressure of CH4 is x and C5H12 is y
x+y=0.5922-----i
1.CH4[g] + 2O2[g] -> CO2[g] + 2 H2O[g]
2.C5H12 + 8O2 → 5CO2 + 6H2O
partial pressure of CH4 is x produce xatm of CO2 and 2xatm of H2O
x + 2x = 3 atm
partial pressure of C5H12 is y produce 5yatm of CO2 and 6yatm of H2O
5y+6y=11y
so the final partial pressure of product mixture will be
3x + 11y = 2.429atm ------ii
solve eq i for x and put in ii
x=0.5922-y -----iii
3(0.5922-y)+ 11y = 2.429atm
y= 0.8155atm
put in iii
x=0.5922-0.8155
x= 0.51atm (Partial pressure of CH4)
mol fraction of CH4=Partial pressure/
Total pressure
=0.51/0.5922
=0.86.
