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3 years ago

What is the length of leg s of the triangle below?

Mathematics

1 answer:

vekshin13 years ago

6 0

Answer:

4 units

Step-by-step explanation:

Let ABC be isosceles right angled ∆ right angled at B

By Pythagoras theorem,

AC² = AB² + BC²

(√32)² = 4² + s²

32 = 16 + s²

s² = 32 - 16

s² = 16

s = √16

s = 4 units.

Therefore s = 4 units

Hope it helps...

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Answer:13 to 14

Step-by-step explanation:

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3 years ago

PLEASE PEOPLE, HELP ME!! Geometry

Oksanka [162]

I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

now i use the the Law of Cosines

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

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3 years ago

The domain of y=ax^2 is all real numbers. Describe the range when (a) a>0 and (b) a<0.

eduard

The range is all positive values...

R{y | y>0}

Range > "Y" such that y is greater than 0

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3 years ago

What is the unit rate of 183 miles in three hours

Ber [7]

61 miles per hour, because if you divide 183/3 you will get 61.

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3 years ago

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A concert hall has three sections: the main floor, the balcony, and the gallery. For a recent concert, 1020 tickets were sold. T

Angelina_Jolie [31]

Answer:

Let the number of balcony seats be b

Let the number of gallery tickets be g

Let the number of main floor tickets be m

b + g + m = 1020

b = 2g

m = b + 225

The number of balcony tickets = 318

The number of gallery tickets = 159

The number of main floor tickets = 543

Step-by-step explanation:

Let the number of balcony seats be b

Let the number of gallery tickets be g

Let the number of main floor tickets be m

i) Therefore we can write b + g + m = 1020

ii) there were twice as many balcony tickets sold as gallery tickets

therefore b = 2g $\Rightarrow$ g = 0.5b

iii) there were 225 more main floor tickets than balcony tickets

therefore m = b + 225

iv) using equation ii) and equation iii) in equation i) we can write

b + g + m = b + 0.5b + b + 225 = 1020 $\Rightarrow$ 2.5b = 795 $\Rightarrow$ b = 318

v) g = 0.5 b = 0.5 $\times$ 318 = 159

vi) m = b + 225 = 318 + 225 = 543

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3 years ago

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