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4 years ago

6

As a defensive measure, forces afloat would typically operate in highly dispersed formations, sometimes covering an area of more

than 40 square miles.A. True.B. False

1 answer:

hoa [83]4 years ago

7 0

Answer:

B - False

Explanation: a dispersed formation means spreading out, more like an attacking or advancing position. This doesn't depict a defensive measure.

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A diffraction grating with 600 lines/mmlines/mm is illuminated with light of wavelength 510 nmnm. A very wide viewing screen is

Ksenya-84 [330]

Answer:

A.2.95 m

B.7

Explanation:

We are given that

Diffraction grating=600 lines/mm

d= $\frac{1 mm}{600}=\frac{1\times 10^{-3} m}{600}=1.67\times 10^{-6} m$

Wavelength of light, $\lambda=510 nm=510\times 10^{-9} m$

l=4.6 m

A.We have to find the distance between the two m=1 bright fringes

$sin\theta=\frac{m\lambda}{d}$

For first bright fringe, =1

$sin\theta=\frac{1\times 510\times 10^{-9}}{1.67\times 10^{-6}}=0.305$

$\theta=sin^{-1}(0.305)=17.76^{\circ}$

The distance between two m=1 fringes

$x=2ltan\theta=2\times 4.6 tan(17.76^{\circ})=2.95 m$

Hence, the distance between two m=1 fringes=2.95 m

B.For maximum number of fringes,

$sin\theta=1$

$sin\theta=\frac{m\lambda}{d}$

Substitute the values

$1=\frac{m\times 510\times 10^{-9}}{1.67\times 10^{-6}}$

$m=\frac{1.67\times 10^{-6}}{510\times 10^{-9}}=3.3\approx 3$

Maximum number of bright fringes on the scree= $2m+1=2(3)+1=7$

8 0

4 years ago

Two identical soccer balls are rolled toward each other. What will be true after they collide head-on

Juliette [100K]

no because there is no chance that it will possibly hit eachother

6 0

2 years ago

What is the formula to calculate Power?

pickupchik [31]

D. Energy / Time is that formula.

4 0

3 years ago

In this wave, there is a vertical line which represents what part of the wave?

nydimaria [60]

Answer:Height

Explanation:

4 0

3 years ago

Read 2 more answers

A solid cylindrical object has a mass of 2.0 kg, a diameter

omeli [17]

Answer:

I = 0.0025 kg.m²

Explanation:

Given that

m= 2 kg

Diameter ,d= 0.1 m

Radius , $R=\dfrac{d}{2}$

$R=\dfrac{0.1}{2}$

R=0.05 m

The moment of inertia of the cylinder about it's axis same as the disc and it is given as

$I=\dfrac{mR^2}{2}$

Now by putting the all values

$I=\dfrac{2\times 0.05^2}{2}$

I = 0.0025 kg.m²

Therefore we can say that the moment of inertia of the cylinder will be 0.0025 kg.m².

4 0

3 years ago