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AnnZ [28]
3 years ago
15

Titin is a spring-shaped elastic protein that attaches to the thick filament and anchors it to the Z-discs of a sarcomere. If ti

tan was denatured, making it straight, it would no longer be able to: a. hold the thick filament in place. b. recoil when stretched and uncoil when the force is removed. c. contract the sarcomere. d. uncoil when stretched and recoil when the force is removed.
Physics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

a. hold the thick filament in place.

Explanation:

Titin is the third most abundant protein in skeletal muscle (after actin and myosin), this protein has a highly elastic potential, and is therefore the protein most responsible for muscle elasticity.

Each titin molecule connects a Z line to the M line of a sarcomere, thus helping to stabilize the position of the thick filament.

So, titin denaturation may result in an inability to hold the thick filament in place.

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An electric light is plugged into a 120-V outlet. If the current in the bulb is 0.50 A, how much electrical energy does the bulb
ioda

Answer:

= 54,000 Joules or 54 kJ

Explanation:

Electrical energy is given by the formula;

E = VIt; where V is the potential difference in volts, I is the current and t is the time in seconds.

Therefore;

Electrical energy = 120 V × 0.50 A × 15 ×60 seconds

                            = 54,000 Joules

Thus; the electrical energy is 54,000 joules or 54 kJ

7 0
3 years ago
What is the equilibrium concentration of ibr?
asambeis [7]
IBR is the thermal decomposition of iodine(I) bromide to produce iodine and bromine. This reaction takes place at a temperature of over 40,5°C and is written as: 

 <span>2IBr ⇄ I2 + Br2
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Equilibrium is a state of dynamic balance where the ratio of the product and reactant concentrations is constant.<span> You can calculate the equilibrium concentration if you know the equilibrium constant Kc (Kc=I^2*Br^2/IBR^2) and the initial concentration for the reaction. The initial concentration is obtained from ICE Table.</span>
3 0
3 years ago
Sam is walking at 2m/s down the hallway when he realized he will be late to class. He speeds up to 4m/s and makes it to English
Salsk061 [2.6K]

Answer:

.5 m/s²

Explanation:

a= (vf-vi)/t

a= (4-2)/4

a=2/4

a= .5 m/s²

8 0
3 years ago
What is the period of a wave if 3 waves passes every 6 seconds
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Time period = time/no. of waves = 6/3 = 2s
4 0
3 years ago
Steam enters the condenser of a steam power plant at 20kPa and a quality of 95% with a mass flow rate of 20,000kg/h. It is to be
avanturin [10]

Answer:

The mass rate of the cooling water required is: 1'072988.5\frac{kg}{h}

Explanation:

First, write the energy balance for the condensator: The energy that enters to the equipment is the same that goes out from it; consider that there is no heat transfer to the surroundings and kinetic and potential energy changes are despreciable.

{m_{w}}*{h_{w}}^{in}+m_s{h_{s}}^{in}=m_w{h_{w}}^{out}+m_s{h_{s}}^{out}

Where w refers to the cooling water and s to the steam flow. Reorganizing,

m_w({h_{w}}^{out}-{h_{w}}^{in})=m_s({h_{s}}^{in}-{h_{s}}^{out})\\m_w=\frac{m_s({h_{s}}^{in}-{h_{s}}^{out})}{({h_{w}}^{out}-{h_{w}}^{in})}

Write the difference of enthalpy for water as Cp (Tout-Tin):

m_w=\frac{m_s({h_{s}}^{in}-{h_{s}}^{out})}{C_{pw}({T_{w}}^{out}-{T_{w}}^{in})}

This equation will let us to calculate the mass rate required. Now, let's get the enthalpy and Cp data. The enthalpies can be read from the steam tables (I attach the tables I used). According to that, {h_{s}}^{out}=251.40\frac{kJ}{kg} and {h_{s}}^{in} can be calculated as:

{h_{s}}^{in}={h_{f}}+x{h_{fg}}=251.40+0.95*2358.3=2491.8\frac{kJ}{kg}.

The Cp of water at 25ºC (which is the expected average temperature for water) is: 4.176 \frac{kJ}{kgK}. If the average temperature is actually different, it won't mean a considerable mistake. Also we know that {T_{w}}^{out}-{T_{w}}^{in}\leq 10, so let's work with the limit case, which is {T_{w}}^{out}-{T_{w}}^{in}=10 to calculate the minimum cooling water mass rate required (A higher one will give a lower temperature difference as a result). Finally, replace data:

m_w=\frac{20000\frac{kg}{h}(2491.8-251.40)\frac{kJ}{kg} }{4.176\frac{kJ}{kgK} (10C)}=1'072988.5\frac{kg}{h}

Download pdf
5 0
3 years ago
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