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AnnyKZ [126]
3 years ago
7

Red Riding Hood sat down to rest and placed her 1.20-kg basket of goodies beside her. A wolf came along, spotted the basket, and

began to pull on the handle with a force of 6.40 N at an angle of 25° with respect to vertical. Red was not going to let go easily, so she pulled on the handle with a force of 12.5 N. If the net force on the basket is straight up, at what angle was Red Riding Hood pulling from the vertical? (show work)
Physics
1 answer:
anygoal [31]3 years ago
3 0

Answer:

  117.6°

Explanation:

The vertical component of a force directed at some angle α from the vertical is ...

  F·cos(α)

We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...

  Fw·cos(25°) + Fr·cos(α) = 0

  cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030

  α ≈ arccos(-0.464030) ≈ 117.6°

Red was pulling at an angle of about 117.6° from the vertical.

_____

<em>Additional comment</em>

That's about 27.6° below the horizontal.

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8 0
3 years ago
An object is initially moving at an unknown velocity. It accelerates at a rate of 1.5m/s2 to a new velocity of 60 m/s in 25 s. W
Alexandra [31]
<h3>Answer:  22.5 m/s</h3>

=====================================================

Work Shown:

acceleration = ( finalVelocity - initialVelocity )/(change in time)

1.5 = (60 - x)/(25)

1.5*25 = 60-x

37.5 = 60-x

x = 60-37.5

x = 22.5

The initial velocity is 22.5 m/s

6 0
3 years ago
Why do elements need to be heated to emit color?
kirill115 [55]
Light carries away the energy. At a room temperature they are at their lowest energy
7 0
3 years ago
A 1500 kg car is moving on a flat, horizontal flat road. If the radius of the curve is 35 m and
Troyanec [42]

The net force on the car is the friction that keeps it on the road, which points toward the center of the circle of the curve. Then by Newton's second law, we have

• net vertical force:

∑ <em>F</em> = <em>N</em> - <em>W</em> = 0

• net horizontal force:

∑ <em>F</em> = <em>Fs</em> = <em>m a</em>

where

<em>N</em> = magnitude of normal force

<em>W</em> = car's weight

<em>Fs</em> = mag. of static friction

<em>m</em> = car's mass

<em>a</em> = <em>v</em> ²/<em>R</em> = mag. of the centripetal acceleration

<em>v</em> = car's speed

<em>R</em> = radius of curve

Now,

• compute the car's weight:

<em>W</em> = <em>m g</em> = (1500 kg) (9.8 m/s²) = 14,700 N

• solve for the mag. of the normal force:

<em>N</em> = 14,700 N

• solve for the mag. of the friction force, using the given friction coefficient:

<em>Fs</em> = 0.5 <em>N</em> = 7350 N

• solve for the (maximum) acceleration:

7350 <em>N</em> = (1500 kg) <em>a</em>   →   <em>a</em> = 4.9 m/s²

• solve for the (maximum) speed:

4.9 m/s² = <em>v</em> ²/ (35 m)   →   <em>v</em> ≈ 13 m/s

4 0
3 years ago
A granite monument has a volume of 25,365.4 cm. The density of granite is 2.7 g/cms. Use this information to calculate the mass
olchik [2.2K]

Answer:

m = 68,486,6 g is the answer.

Explanation:

To calculate mass you use formula:

m= V*r

To avoid remembering this formula you can see the type of unit on each given variable. We can see that we have g/cm^3 and cm^3. If we multiply them, we negate cm^3 and cm^3 and we are left with g which is unit for mass.

Hope I helped! ☺

8 0
3 years ago
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