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Ksivusya [100]
3 years ago
12

Loli-land candy store sells a 12 ounce bag of 60 mints. How many ounces does each mint way?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:The answer is .2 ounces

Step-by-step explanation: This is because 60 ounces divided by 12 candies is equal to .2 ounces.

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Schach [20]

Answer:

y+3=4(x-5)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-3)=4(x-5)

y+3=4(x-5)

5 0
3 years ago
How do i find y=1/2x+2 on a scatter plot <br>(Question 14)
Ainat [17]

Answer:

la cuestión is 15/7xt2

4 0
3 years ago
Identify the slope represented in the graph below.
Vedmedyk [2.9K]
Answer:
The slope is -2
Explanation:
I choose two points on the graph (0,-2) and (-1,0) and put it into the slope form using two coordinate pairs which is y-y/x-x and got -2/1 which simplifies down to -2
5 0
3 years ago
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
Q11.
Kamila [148]

Answer:

Step-by-step explanation:

The area of a trapezium is given as;

Area = \frac{1}{2}(a + b)h

where: a is the length of the upper side, b is the length of its base and h is its height.

This implies that; a = x - 4, b = x + 5, h = 2x and area = 351

Thus,

351 =  \frac{1}{2}((x - 4) + (x + 50)) 2x

      = (x - 4 + x + 5) x

531 = (2x + 1) x

      = 2x^{2} + x

So that;

2x^{2} + x - 531 = 0

This gives a quadratic equation.

5 0
3 years ago
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