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Anon25 [30]
3 years ago
14

A restaurant manager can spend at most $400 a day for operating costs and payroll. It costs $100 each day to operate the bank an

d $50 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at most: 50x + 100 ≤ 600
Mathematics
2 answers:
nevsk [136]3 years ago
4 0

Answer:

x < = 10

Step-by-step explanation:

i did it on photo math so yah

horrorfan [7]3 years ago
3 0

Answer:

The restaurant Manager can afford 6 employees for the day.

Step-by-step explanation:

Manager can spend at most of $400.

Total Money ≤ $400

Cost to operate bank = $100

Cost for each employee = $50

Let number of employees for the day bex

Hence the equation will become;

50x + 100 \leq 400

Solving this equation we get;

50x + 100 \leq 400\\50x \leq 400-100\\50x \leq 300\\x\leq \frac{300}{50}\\\\x\leq 6

Hence, The restaurant Manager can afford 6 employees for the day.

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Step-by-step explanation:

Let us revise the cases of congruence  

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∵ SR bisects angle TSQ ⇒ given

∴ ∠TSR ≅ ∠QSR

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∵ m∠T ≅ m∠Q

∵ m∠TSR ≅ m∠QSR

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∴ Δ RTS ≅ ΔRQS ⇒ AAS postulate

Triangle RTS is congruent to RQS by AAS postulate of congruent

Learn more:

You can learn more about the congruent in brainly.com/question/3202836

#LearnwithBrainly

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