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Anon25 [30]
4 years ago
14

A restaurant manager can spend at most $400 a day for operating costs and payroll. It costs $100 each day to operate the bank an

d $50 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at most: 50x + 100 ≤ 600
Mathematics
2 answers:
nevsk [136]4 years ago
4 0

Answer:

x < = 10

Step-by-step explanation:

i did it on photo math so yah

horrorfan [7]4 years ago
3 0

Answer:

The restaurant Manager can afford 6 employees for the day.

Step-by-step explanation:

Manager can spend at most of $400.

Total Money ≤ $400

Cost to operate bank = $100

Cost for each employee = $50

Let number of employees for the day bex

Hence the equation will become;

50x + 100 \leq 400

Solving this equation we get;

50x + 100 \leq 400\\50x \leq 400-100\\50x \leq 300\\x\leq \frac{300}{50}\\\\x\leq 6

Hence, The restaurant Manager can afford 6 employees for the day.

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vazorg [7]

Answer:

y=1

Step-by-step explanation:

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3 0
3 years ago
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3(r+2)+5(2-r) =-32 can someone tell em the answer to that please
Alex17521 [72]

Answer:

r = 24

Step-by-step explanation:

3(r+2)+5(2−r)=−32

Step 1: Simplify both sides of the equation.

3(r+2)+5(2−r)=−32

(3)(r)+(3)(2)+(5)(2)+(5)(−r)=−32(Distribute)

3r+6+10+−5r=−32

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Step 2: Subtract 16 from both sides.

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Step 3: Divide both sides by -2.

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8 0
3 years ago
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A class has 4 boys and 10 girls what is the ratio in the simplest form that compares numbet boys to total number of students
polet [3.4K]

Answer: 2 : 7

Step-by-step explanation:

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3 years ago
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Verizon [17]
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Arlecino [84]

Answer:

m would be 1

Step-by-step explanation:

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3 years ago
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