The final temperature of the sample, in degrees Celsius is 36.6 °C
<h3>Heat capacity of a substance</h3>
From the question, we are to determine the final temperature of the sample
From the formula for heat capacity, we have that
Q = mcΔT
Where Q is the heat energy
m is the mass
c is the specific heat capacity of the subtance
ΔT is the change in temperature (
)
From the given information
m = 687.6 g
Q = 8284.4 J
= 23.1 °C
Putting the parameters into the equation, we get
![8284.4 = 687.6 \times 0.89 \times (T_{f} -23.1)](https://tex.z-dn.net/?f=8284.4%20%3D%20687.6%20%5Ctimes%200.89%20%5Ctimes%20%28T_%7Bf%7D%20-23.1%29)
NOTE: Specific heat capacity of aluminum = 0.89 J/ g °C
Then,
![8284.4 = 611.964 \times (T_{f} -23.1)](https://tex.z-dn.net/?f=8284.4%20%3D%20611.964%20%20%5Ctimes%20%28T_%7Bf%7D%20-23.1%29)
![(T_{f} -23.1)= \frac{8284.4}{611.964}](https://tex.z-dn.net/?f=%28T_%7Bf%7D%20-23.1%29%3D%20%5Cfrac%7B8284.4%7D%7B611.964%7D)
![(T_{f} -23.1)= 13.5](https://tex.z-dn.net/?f=%28T_%7Bf%7D%20-23.1%29%3D%2013.5)
![T_{f} = 13.5 + 23.1](https://tex.z-dn.net/?f=T_%7Bf%7D%20%3D%2013.5%20%2B%2023.1)
![T_{f} = 36.6 \ ^\circ C](https://tex.z-dn.net/?f=T_%7Bf%7D%20%3D%2036.6%20%5C%20%5E%5Ccirc%20C)
Hence, the final temperature of the sample, in degrees Celsius is 36.6 °C
Learn more on Heat capacity of a substance here: brainly.com/question/13439286