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Nataly [62]
3 years ago
9

How has the world's changing climate today affected glaciers and sea levels

Chemistry
2 answers:
zaharov [31]3 years ago
7 0

Answer:

It has caused sea levels to rise and caused glaciers to melt.

Explanation:

Because glaciers and ice caps are melting rapidly and they store about 1.7% all of Earth's water, causing sea levels to rise.

arsen [322]3 years ago
5 0

Answer:

Global warming is causing global mean sea level to rise in two ways. First, glaciers and ice sheets worldwide are melting and adding water to the ocean. ... A third, much smaller contributor to sea level rise is a decline in the amount of liquid water on land—aquifers, lakes and reservoirs, rivers, soil moisture.

Explanation:

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Which molecule is methylamine?
love history [14]

A.

An amine refers to a nitrogen-based compound. Since A is the only option with nitrogen, that would be the answer.

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3 years ago
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Do you think sodium carbonate is an acid or base?
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I just looked it up and it says "Na2CO3 (sodium carbonate) is neither an acid nor a base. It is a salt..." I really hoped this helped you, if not I'm sorry.
7 0
4 years ago
During an effusion experiment, a certain number of moles of an unknown gas passed through a tiny hole in 50 seconds. Under the s
mafiozo [28]
50/35 = √x/ √31.9988 g
50 x (√31.9988/ 35) = √x

√x = 8.081...

x= 65.30...

x= 70 g/ mol


3 0
3 years ago
Which is one way that Dalton's atomic theory has been shown to be incorrect?
KATRIN_1 [288]
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6 0
4 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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