The electron dot diagram of helium has six fewer electrons than the electron dot diagram of neon.
hope this helps!
Answer:
New temperature T2 = -124.7 °C
Explanation:
Given:
Old volume V1 = 135 cm³
New volume V2 = 140 cm³3
Old temperature T1 = 143 K
Find:
New temperature T2
Computation:
V1 / T1 = V2 / T2
135 / 143 = 140 / T2
New temperature T2 = 148.3 K
New temperature T2 = 148.3 - 273
New temperature T2 = -124.7 °C
Answer:
Explanation:
When determining empirical formulas of hydrates we have to find the mass of water which left the hydrate when heating The sample. This amount of water calculated will provide us with the correct ratio of moles water / moles anhydrate since moles water > moles anhydrate. The mistake might have been done while determining the water that left the sample so then we see and impropre result in ratios.
Answer:
a) If the solvent-solute interactions in a mixture are <u>stronger than</u> the solvent-solvent interactions and the solute-solute interactions, a homogeneous solution forms.
b) If the solvent-solute interactions in a mixture are <u>weaker than</u> the solvent-solvent interactions and the solute-solute interactions, the formation of a homogeneous solution is uncertain.
Explanation:
The solubility of solute in given solvent mainly depends upon the intermolecular interactions between the solvent and the solute. If the solute is surrounded and solvated by the solvent then the solute will dissolve in that solvent. Therefore, in order to dissolve the solute must form stronger interactions with the solvent as compared to the solute solute interactions or solvent solvent interactions.
Example:
When NaCl is added to water the partial negative oxygen of water is attracted to Na⁺ of NaCl and the partial positive hydrogen of water is attracted to Cl⁻ of NaCl. These new interactions between the NaCl ions and water are stronger than the interactions between water molecules and NaCl molecules themselves hence, results in solubility of NaCl in water.
On the other hand, if NaCl is added to Hexane (C₆H₁₄) it fails to make strong interactions with the solvent molecules resulting in insolubility of NaCl in hexane.
