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NemiM [27]
4 years ago
10

Both pyramids in the figure have the same base area as the prism. The ratio of the combined volume of the pyramids to the volum

e of the prism,expressed as a fraction in simplest form,is .
There are no choices. :/

Mathematics
1 answer:
defon4 years ago
5 0
At first, I thought this was going to be a dog of a bear of a problem,
but then I fixated it with my steely burning gaze and it fell apart for me.

The volume of a pyramid is   (1/3) (base area) (height)

Each of these pyramids has the same base area and the
same height, so ...

      Volume of the lower pyramid = (1/3) (base area) (height)
      Volume of the upper pyramid = (1/3) (base area) (height)

Combined volume of both pyramids = (2/3) (base area) (height) .

Now, how do the pyramids relate to the rectangular prism ?

Their base area is  (length x width) of the prism, and
their height is  (1/2 the height) of the prism.

From here, we'll work with the dimensions of the prism ... L, W, and H .

Combined volume of the pyramids = (2/3) (L x W) (1/2 H)

                                                           =  (1/3) (L x W x H) .

Volume of the prism  =  (L x W x H)

The pyramids occupy 1/3 the volume of the prism.

The ratio is  1/3 .
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Yakvenalex [24]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
PLEASE HELP!! DUE SOON
mrs_skeptik [129]

Answer:

b=3a/8

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Step-by-step explanation:

b/a=k ( k is the constant proportional)

3/8=9/24=15/40

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b=3a/8

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I hope this is right answer

7 0
3 years ago
Dose 36 go into 50? Plzz help
Alik [6]
<span>Just once with a remainder of 14
</span><span>
</span>
8 0
4 years ago
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A surveying team set up some equipment 104104 ft from the base of a tree in order to sight the top of the tree. From ground leve
jarptica [38.1K]

Answer:

Relative error = 0.0254 %

Step-by-step explanation:

Given details

Height of equipment from base is 104 ft

Elevation angle is 27.5 degree

From figure we have

tan\theta = \frac{x}{104} .........1

tan(27.5) = \frac{x}{104}

x  = 54.13 ft

differentiating 1st eq wrt x

\frac{d}{dx} tan\theta = \frac{d}{dx} [\frac{x}{104}]

sec^2\theta \frac{d\theta}{dx} = \frac{1}{104}

Taken d\theta \ as \Delta x \ and\  dx = \Delta x for minute change

\Delta x = 1.5% x

             = 0.015 \times 54.13 = 0.8119 ft

from sec^2 \theta \frac{d\theta}{dx} = \frac{1}{104}

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\Delta \theta = \frac{1}{104 \times 1.115} 0.8119

\Delta \theta  = 0.007

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4 0
4 years ago
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Sav [38]

Answer:

28.42 > 28.404

it is true

3 0
3 years ago
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