Answer:
Carbon Monoxide / Carbon Dioxide / Sulfur and Nitrogen Dioxide
Explanation:
The question is incomplete, complete question is :
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.
Answer:
33.11 millimoles of acetate we will need to add to this solution.
Explanation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
Where :
tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid
[salt] = Concentration of salt
[Acid] = Concentration of salt
We have:
pH = 5.26

[salt] =
= ?
[acid] = ![[CH_3COOH]=10.0 mmol](https://tex.z-dn.net/?f=%5BCH_3COOH%5D%3D10.0%20mmol)
![[CH_3COO^-]=33.11 mmol](https://tex.z-dn.net/?f=%5BCH_3COO%5E-%5D%3D33.11%20mmol)
33.11 millimoles of acetate we will need to add to this solution.
Answer:
atomic mass 112.4 and Cadmium (Cd)
Explanation:
You have 73.35 g of MO.
After the reaction the O is removed and you only have M which the mass is 64.21 g.
With that you can calculate the mass of O removed:
Mass of O = 9.14 g
Mass = AM * moles ; (AM : Atomic Mass)
9.14 = 16 * moles
moles = 9.14 / 16
moles = 0.57125
The formula of the metal oxide is MO, meaning it has 1 mole of M per mole of O. 73.35 had 0.57125 moles of O, then it also had 0.57125 moles of M, and the remaining mass of 64.21 g represents those moles
Mass = AM * moles ; (AM : Atomic Mass)
64.21 = AM * 0.57125
AM = 64.21/0.57125 = 112.4 amu
The metal with an atomic mass of 112.4 is Cadmium (Cd), therefore the metal oxide is CdO
Answer:
<h2>9.26 L</h2>
Explanation:
The density of a substance can be found by using the formula

From the question we have

We have the final answer as
<h3>9.26 L</h3>
Hope this helps you