Answer:
The answer to your question is given below.
Explanation:
Data obtained from the question include:
Sodium, Na => 1s2 2s2 2p6 3s1
Magnesium, Mg => 1s2 2s2 2p6 3s2
Aluminium, Al => 1s2 2s2 2p6 3s2 3p1
Sodium has 1 valence electron. If we remove the valence electron, sodium metal will become an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
Magnesium has 2 valence electrons. If we remove the valence electrons, magnesium metal will be an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
Aluminium has 3 valence electrons. If we remove the valence electrons, aluminum metal will become an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
The dimensions of field are
. The area can be calculated as follows:
![A=l\times b=0.1020 km\times 0.0640 km=6.526\times 10^{-3}km^{2}](https://tex.z-dn.net/?f=A%3Dl%5Ctimes%20b%3D0.1020%20km%5Ctimes%200.0640%20km%3D6.526%5Ctimes%2010%5E%7B-3%7Dkm%5E%7B2%7D)
Converting
,
1 km =1000 m
Thus, ![1km^{2}=10^{6}m^{2}](https://tex.z-dn.net/?f=1km%5E%7B2%7D%3D10%5E%7B6%7Dm%5E%7B2%7D)
or, ![6.526\times 10^{-3}km^{2}=6.526\times 10^{3}m^{2}](https://tex.z-dn.net/?f=6.526%5Ctimes%2010%5E%7B-3%7Dkm%5E%7B2%7D%3D6.526%5Ctimes%2010%5E%7B3%7Dm%5E%7B2%7D)
Since, cost of new artificial turf is
, thus, cost for
will be:
![Cost= \$ 9.50/m^{2}\times 6.528\times 10^{3}m^{2}=\$ 62016](https://tex.z-dn.net/?f=Cost%3D%20%5C%24%209.50%2Fm%5E%7B2%7D%5Ctimes%206.528%5Ctimes%2010%5E%7B3%7Dm%5E%7B2%7D%3D%5C%24%2062016)
Therefore, cost of artificial turf for field will be
.
The atom contain 6 neutrons, if that's the question
Answer:
(a) gas c has the highest partial pressure
(b) gas b has the lowest partial pressure
(c) 0.233 atm
Explanation:
In the given figure, the number of atoms of each gas is:
gas a = 4
gas b = 3
gas c = 5
gas
= 4
Using the total gas pressure of 0.931 atm and the partial pressure of each gas is directly proportional to its mole fraction. Therefore,
Partial pressure of gas a = 4/(4+3+5+4) * 0.931 = 0.233 atm
Partial pressure of gas b = 3/(4+3+5+4) * 0.931 = 0.175 atm
Partial pressure of gas c = 5/(4+3+5+4) * 0.931 = 0.291 atm
Partial pressure of gas
= 4/(4+3+5+4) * 0.931 = 0.233 atm
(a) gas c has the highest partial pressure
(b) gas b has the lowest partial pressure
(c) 0.233 atm