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prisoha [69]
3 years ago
12

What quadrant does sec(theta)>0 and cot(theta)<0 lie in

Mathematics
1 answer:
lora16 [44]3 years ago
4 0
\sec\theta=\dfrac1{\cos\theta}>0\implies\cos\theta>0

This happens in the first and fourth quadrants.

Since cosine is positive,

\cot\theta=\dfrac{\cos\theta}{\sin\theta}

and this happens in the third and fourth quadrants.

This means both conditions can only occur in the fourth quadrant.
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Read 2 more answers
calculate the distance between the points E=(-1,-5) and F=(-8,1) in the coordinate plane. Give an exact answer (not a decimal ap
Elena L [17]

Answer:

The answer is

<h2>\sqrt{85}  \:  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x_1 - x_2})^{2} +  ({y_1 - y_2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

E(-1,-5) and F(-8,1)

The distance between them is

|EF|  =  \sqrt{ ({ - 1 + 8})^{2}  +  ({ - 5 - 1})^{2} }  \\  =  \sqrt{ {7}^{2}  +  ({ - 6})^{2} }  \\  =  \sqrt{49 + 36}  \:  \:  \:  \:  \:  \:  \:  \\  =  \sqrt{85}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

\sqrt{85}  \:  \:  \:  \: units

Hope this helps you

7 0
3 years ago
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