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prisoha [69]
3 years ago
12

What quadrant does sec(theta)>0 and cot(theta)<0 lie in

Mathematics
1 answer:
lora16 [44]3 years ago
4 0
\sec\theta=\dfrac1{\cos\theta}>0\implies\cos\theta>0

This happens in the first and fourth quadrants.

Since cosine is positive,

\cot\theta=\dfrac{\cos\theta}{\sin\theta}

and this happens in the third and fourth quadrants.

This means both conditions can only occur in the fourth quadrant.
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Solve the system of equations using elimination 2x+y=3 and 3x-y=12
Eddi Din [679]
2x + y = 3
3x - y = 12
Add both equations
5x = 15, x = 3
2(3) + y = 3
6 + y = 3, y = -3
Solution: x = 3, y = -3... or (3,-3)
3 0
3 years ago
a big cruise ship dropped anchor off the Caribbean island of antigua. the heavy anchor dropped into the water at a rate of 2.5 m
AysviL [449]

Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell

                                     (2.5 m/s) x (45 s)  =  112.5 meters .

If it wound up only 40 meters underwater, then it must have fallen

                                      (112.5 m  -  40 m)  =  72.5 meters

from its storage position on the big cruise ship, 
before it ever reached the water.

Since it was falling at the rate of  2.5 m/s, it took

                                     (72.5 m) / (2.5 m/s)  =  29 seconds

to get down to the water surface after it started dropping.

6 0
3 years ago
Can someone help me please?
taurus [48]

Answer:

437.4 meters squared

Step-by-step explanation:

7.2*4.5=32.4=b

3*4.5=13.5=h

b*h=a

32.4*13.5=437.4m^2

3 0
3 years ago
Read 2 more answers
577 rounded to the nearest ten
anygoal [31]

The correct answer 580

Hope this helps

7 0
2 years ago
Read 2 more answers
The weights (to the nearest pound) of some boxes to be shipped are found to be:. Weight 65 68 69 70 71 72 90 95 frequency 1 2 5
Lena [83]
So the mean is 72.97

We need to subtract the mean from each value and square it.
(65-72.97)^2= 63.5209
(68-72.97)^2=24.7009
(69-72.97)^2=15.7609
(70-72.97)^2=8.8209
(71-72.97)^2= 3.8809
(72-72.97)^2=0.9409
(90-72.97)^2=290.0209
(95-72.97)^2=485.3209

Now we add up the new values ( also consider their frequency) and find their mean.
Add the values
63.5209+(2 •24.7009=49.4018)+(5•15.7609=78.8045)+(8•8.8209=70.5672)+(7•3.8809=27.1663)+(3•0.9409=2.8227)+(2•290.0209=580.0418)+(2•485.3209=970.6418)= 1,842.967
Divide by total numburs to find the mean
1,842.967/ 30=61.43223333

The standar deviation is the square root of the mean so is
Square root of 61.43223333=7.837871735
Round to the nearest tenth
Standard Deviation is 7.8



7 0
3 years ago
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