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Ivahew [28]
3 years ago
11

What is 4 to the square root of 2

Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0
Approximately 7.10299
shutvik [7]3 years ago
3 0

Answer:

7.10299

Step-by-step explanation:

4^{\sqrt{2} } is best evaluated in a calc.

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The manufacturer of widgets spends $5 to make each widget and sells them for $8. The manufacturer also has fixed costs each mont
Minchanka [31]

Answer:

400

Step-by-step explanation:

The manufacturer spends $5 to make each widget and sells them for $8.  This means that each widget gives him a profit of $3.

8 - 5 = 3

You need to figure out how many widgets it will take for the manufacturer to make up for the costs each month ($1200).

3x = 1200

(3x)/3 = 1200/3

x = 400

The manufacturer needs to sell 400 widgets.

3 0
3 years ago
Read 2 more answers
Paul could play 16 songs. He learns some new songs. Now, Paul can play 23 songs. In the first box, enter an equation to represen
Murrr4er [49]
16 + s = 23


-16      =-16

s= 7
8 0
3 years ago
Given the equation of a trend line (y=15x+21), can you find the exact amount of sales given the advertising cost? Explain
alukav5142 [94]

Answer: YOU MUST USE PEMDAS

Step-by-step explanation:

pls give me brainliest im almost lvled up

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!!!!!! DUE SOON
Sergio039 [100]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t


now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)


\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)

6 0
3 years ago
Help!
Anastaziya [24]
I'm doing the exact same one an i got 48 cubic units for the volume. I still have to draw the rectangular figure though.
6 0
3 years ago
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