Question

Find the magnitude of the torque that acts on the molecule when it is immersed in a uniform electric field of 6.19×105 N/C with its electric dipole vector at an angle of 69.9∘ from the direction of the field.

Answer 1

Answer:

$\tau=5.81\times 10^5p\ N-m$

Explanation:

We have,

Electric field, $E=6.19\times 10^5\ N/C$

The electric dipole vector at an angle of 69.9 degrees from the direction of the field.

The torque acting on a molecule is given by :

$\tau=p\times E\\\\\tau=pE\sin\theta$

p is electric dipole moment

$\tau=p\times 6.19\times 10^{5}\times \sin (69.9)\\\\\tau=5.81\times 10^5p\ N-m$

So, the magnitude of the torque acting on the molecule is $5.81\times 10^5p\ N-m$.