Answer:
its terminal velocity is 19.70 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
Explanation:
Firstly,
given that
m = 580g = 0.58kg
Area A = 0.11 * 0.22 = 0.0242m
g = 9.8
idensity constant p = 1.21 kg/m^3
the terminal velocity of the sphere Vt is ;
Vt = √ ( 2mg / pCA)
we substitute
Vt = √ ( (2*0.58*9.8) / (1.21*1*0.0242)
Vt = √ (11.368 / 0.029282)
Vt = √ ( 388.22)
Vt = 19.70 m/s
its terminal velocity is 19.70 m/s
What will be the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance?
The Velocity of the person is;
V2 = √ 2ax
V2 = √ ( 2 * 9.8 * 4 )
V2 = √ (78.4)
V2 = 8.85 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
True .......................................
Explanation:
<em><u>GIVEN </u></em><em><u>:</u></em>
Work done(W) = 40 J
Time(t) = 4 s
Power (P) = ?
<em><u>We </u></em><em><u>know </u></em><em><u>that:</u></em>
W = P×t
Therefore,
P= W/t
=40/4
= 10 W
<em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em>
Power = (voltage) x (current)
(1,200 W) = (120 V) x (current)
Current = (1,200 watt) / (120 volt) = 10 Amperes.
How long the heater heats is irrelevant. The current
is flowing all the time, whenever the heater is running.