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coldgirl [10]
3 years ago
5

Delta waves occur during

Physics
1 answer:
irakobra [83]3 years ago
7 0
Stage sleep I think but not sure
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Please answer!!! I’m desperate
rodikova [14]

a is the answer hope this helps

8 0
4 years ago
A syringe containing 1.55 ml of oxygen gas is cooled from 95.3 °c to 0.0 °c. what is the final volume of oxygen gas?\
irinina [24]
Consider the gas to be an ideal gas (it will obey all the introductory gas laws). Also you have to note that the gas will not change phase. It won't.

T_s (Temperature Start) = 95.3o C = 95.3 + 273 = 368.3 oK (degrees Kelvin)
T_e (Temperature End) = 0o C + 273 = 273 oK

Initial volume = Vi = 1.55 mL (no need to change to Liters. The answer will be in mL

 Vi /Ts =  Ve / Vs Ve is the unknown volume that you seek.
1.55 / 368.3  =  Ve / 273
Ve = 1.55 * 273 / 368.3
Ve = 1.1489 mL

If your teacher is concerned about Sig digs, then 0.0 has only two.
Your answer should be 1.1 mL, but I'll give you the choice.



3 0
4 years ago
Whats a non-example for average speed
jonny [76]

A vector quantity is defined by magnitude and direction. For example, we might say that a car has an average speed of 25 miles per hour. Its average velocity might be 25 miles per hour due east.

6 0
3 years ago
Read 2 more answers
Distinguish between an energy transfer and an energy transformation in the following situation: A heat lamp warms a baby zebra.
Musya8 [376]

Energy transfer is when a energy transfers from a body/object to another.

Energy transformation is when energy is transformed into another form.

There is an energy transfer from the heat lamp to the baby zebra.

5 0
3 years ago
A ball is thrown straight up into the air with an initial velocity of 50 ft/sec. The height h(t) of the ball after t seconds is
Scrat [10]

Answer:

The average velocity for the time period beginning when t=1 and lasting 0.1 seconds = 16.40 ft/s.

Explanation:

Given that the height of the ball at time t is

\rm h(t) = (50 t-16t^2)\ ft.

The average velocity of an object is defined as the total displacement covered by the particle divided by the total time taken in covering that displacement.

If \rm h_1,\ h_2 are the heights of the ball at time \rm t_1 and \rm t_2, then the total displacement covered by the ball from time \rm t_2 to \rm t_1 is \rm h_2-h_1.

Thus, the average velocity of the ball for the time interval \rm t_2-t_1  is given by

\rm v_{av}=\dfrac{h_2-h_1}{t_2-t_1}.

For the time interval, beginning when t = 1 second and lasting 0.1 seconds,

\rm t_1=1\ sec.\\t_2 = 1\sec + 0.1\ sec = 1.1\ sec.\\\\h_1=50\times 1-16\times 1^2=34\ ft.\\h_2=50\times 1.1-16\times 1.1^2=35.64\\\\Therefore,\\\\v_{av} = \dfrac{35.64-34}{1.1-1}=16.40\ ft/s.

7 0
4 years ago
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