L=2+W
A=LW
A=(2+W)W
20=2W+W^2
0=W^2+2W-20
use quadratic
fr
aw^2+bw+C=0
w=(-b+/-sqrt(b^2-4ac))/2a
a=1
b=2
c=-20
w=(-2+/-sqrt(2^2-4(1)(-20)))/2(1)
w=(-2+/-sqrt(4+80))/2
w=(-2+/-sqrt(84))/2
w=(-2+/-2sqrt(21))/2
w=1+/-sqrt(21)
aprox
w=-3.58 or 5.58
cannot have negative width
w=5.58
round
w=5.6
sub
l=2+w
l=2+5.6
l=7.6
legnth=7.6m
width=5.6m
Answer: A streetlight casts a shadow 15 feet long. At the same time, a 18-foot flag pole casts a shadow 10 feet long. How tall is the tree? | Socratic A tree casts a shadow 15 feet long.
Based on the given problem above, this would appear that,
one pound of peanuts = 0.60*2 = $1.2
one pound of cashews = $2
Therefore, the cost of one pound of peanuts is $1.2.
The total cost of two pounds of peanuts and one pound of cashews would be this: 1.2 + 1.2 + 2 = $4.4
Hope this answers your question.
Answer:
Surface area of square pyramid is computed as follows:
A = a² + a*√(a² + 4h²)
where <em>a</em> is the base length and <em>h</em> is the height.
If a model of the square pyramid is scaled down by a factor of x, then the surface area will be:
A' = (a/x)² + (a/x)*√[(a/x)² + 4(h/x)²]
A' = a²/x² + a/x * √[a²/x² + 4h²/x²]
A' = a²/x² + a/x * √[(a² + 4h²)/x²]
A' = a²/x² + a/x * √(a² + 4h²)/√x²
A' = a²/x² + a/x² * √(a² + 4h²)
A' = 1/x² * [a² + a*√(a² + 4h²)]
A' = 1/x² * A
That is, the surface area will be 1/x² times the original surface area. If h = 25 ft and a = 15 ft:
A = 15² + 15*√(15² + 4(25)²) = 1008.02 ft²
The factor is not mentioned in the question, nevertheless, the area will be 1008.02/factor² ft²
Answer:
the answer is mx +B plus the quradratic formula
