Determine the maximum number of zeros of the polynomial function
1 answer:
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By definition, the unit vector of v = (a,b) is
Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
(3,5)/√[3² + 5²]
= (3,5)/√34
The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65
Answer:
The unit vector of v₁ in the direction of |v₁} is
The unit vector of v₂ in the directin of |v₂| is
Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
(3,5)/√[3² + 5²]
= (3,5)/√34
The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65
Answer:
The unit vector of v₁ in the direction of |v₁} is
The unit vector of v₂ in the directin of |v₂| is