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harkovskaia [24]
3 years ago
8

When the day was over , everybody had earned at least 1 medal, and 32 each got 2 medals. In all, 194 each of gold, silver , and

bronze medals were given out . How many students played in the games?
Mathematics
1 answer:
Orlov [11]3 years ago
8 0

Answer:

32 X 2= 64

194-64 = 130 students

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List 3 values that would make this inequality true. 10≥2n<br> 10<br> 0<br> 5<br> 8<br> 6<br> 7<br> 2
GuDViN [60]

Answer:

0, 2, 5

Step-by-step explanation:

10 ≥ 2n

Divide both sides by 2

5 ≥ n

Flip

n ≤ 5

Values less than or equal to 5

0, 2, 5

7 0
3 years ago
What is the unit price of a can of cat food if 3 cans cost $2.41? How much does one can cost? round to the nearest cent, only to
Harrizon [31]
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Find the sum of the first 47 terms of the following series, to the nearest integer.
Leokris [45]

Answer:

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ is 4,888

Step-by-step explanation:

The given series is;

12, 16, 20, ...,

Therefore, the first term of the series is, a = 12

The common difference of series is found as follows;

The difference between subsequent terms, 12 and 16 is  16 - 12 = 4

The difference between subsequent terms, 16, and 20 is  20 - 16 = 4

Therefore, the common difference, d = 4

The series is therefore an arithmetic projection, AP

The sum of the first 'n' terms of an AP, Sₙ, is given as follows;

S_n = \dfrac{n}{2} \cdot \left [2 \cdot a + (n - 1)\cdot d \right ]

(47/2)*(2*12+(47-1)*4)

The sum of the first 47 terms is therefore given as follows;

S_n = \dfrac{47}{2} \cdot \left [2 \times 12 + (47 - 1)\times 4 \right ] = 4,888

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ = 4,888

5 0
3 years ago
1.6 - 1.3 mathematics
elena-14-01-66 [18.8K]
Answer: 0.3 :) :) :) :)
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Answer:

C and E i think

Step-by-step explanation:

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3 years ago
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